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Zolol [24]
4 years ago
7

A company has developed a new computer microprocessor whose average lifetime is unknown. In order to estimate this average, 300

microprocessors are randomly selected from a large production line and tested; their average lifetime is found to be 7 years. The 300 microprocessors represent a:______
Mathematics
2 answers:
wlad13 [49]4 years ago
7 0

Answer:

SAMPLE

Step-by-step explanation:

inn [45]4 years ago
3 0

Answer: Sample

Hope this helps

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A regular pentagon has an apothem measuring 3 cm and a perimeter of 21.8 cm. What is the area of the pentagon, rounded to the ne
yaroslaw [1]
The area of a regular polygon is given by
  A = (1/2)Pa
where P is the perimeter, and "a" is the apothem.

For your numbers, the area is
  A = (1/2)(21.8 cm)(3 cm) = 32.7 cm²
8 0
3 years ago
Read 2 more answers
What is the value of 7(10 – 16) + 8 ÷ 2?
Artyom0805 [142]

Answer:

−38

First do 10-16 which is -6

(7)(−6)+8/2

=−42+8/2

8/2 equals 4 so add -42 to 4

=−42+4

=−38

8 0
3 years ago
Read 2 more answers
Help me out thanks (:
Lisa [10]

Answer:

2x - 3

Step-by-step explanation:

To find this simplified equation, you divide the whole numerator by the denominator, which results in the equation listed above.

8 0
4 years ago
Find the surface area of the rectangular prism.
Nataly_w [17]

Answer:

130 ft^2

Step-by-step explanation:

SA= surface area

SA= 2*l*w + 2*l*h + 2*w*h

l= length = 10

w= width =5

h = height = 1

SA= 2*l*w + 2*l*h + 2*w*h

SA= 2*10*5 +2*10*1+2*5*1

SA= 100+20+10

SA= 130 ft^2

4 0
4 years ago
A fair coin is tossed three times and the events A, B, and C are defined as follows: A: \{ At least one head is observed \} B: \
Yanka [14]

Answer:

a) P(A)=0.875

b) \text{P(A or B)}=0.875

c) \text{P((not A)  or B  or (not C))}=0.625

Step-by-step explanation:

Given : A fair coin is tossed three times and the events A, B, and C are defined as follows: A: At least one head is observed, B: At least two heads are observed, C: The number of heads observed is odd.

To find : The following probabilities by summing the probabilities of the appropriate sample points ?

Solution :

The sample space is

S={HHH,HHT,HTT,HTH,TTT,TTH,THH,THT}

n(S)=8

A: At least one head is observed

i.e. A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

n(A)=7

B: At least two heads are observed

i.e. B={HHH,HTT,TTH,THT}

n(B)=4

C: The number of heads observed is odd.

i.e. C={HHH,HTT,THT,TTH}

n(c)=4

a) Probability of A, P(A)

P(A)=\frac{n(A)}{n(S)}

P(A)=\frac{7}{8}

P(A)=0.875

b) P(A or B)

Using formula,

\text{P(A or B)}=P(A)+P(B)-\text{P(A and B)}

\text{P(A or B)}=\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{\text{n(A and B)}}{n(S)}

\text{P(A or B)}=\frac{7}{8}+\frac{4}{8}-\frac{4}{8}

\text{P(A or B)}=\frac{7}{8}

\text{P(A or B)}=0.875

(c) P((not A)  or B  or (not C))

A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

not A = {TTT} = 1

B={HHH,HTT,TTH,THT}

C={HHH,HTT,THT,TTH}

not C = {HHT,HTH,THH,TTT} = 4

So, not A or B or not C = {HHH,HHT,HTH,THH,TTT}=5

\text{P((not A)  or B  or (not C))}=\frac{5}{8}

\text{P((not A)  or B  or (not C))}=0.625

4 0
3 years ago
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