Question

PLEASE DO 41 AND 45!!!!!!

Answer 1

Answer:

see below

Step-by-step explanation:

41

-4 ≤2+4x<0

Subtract 2 from all sides

-4-2 ≤2-2+4x<0-2

-4 ≤2+4x<0

Divide all sides by 4

-6/4 ≤4x/4<-2/4

-3/2 ≤x <-1/2

graph is attached

45

2x-3 ≤-4  or 3x+1 ≥4

Lets solve the left side first

2x-3≤-4

Add 3 to each side

2x-3+3 ≤-4+3

2x ≤-1

Divide by 2

2x/2  ≤-1/2

x  ≤-1/2

Now solve the right inequality

3x+1 ≥4

Subtract 1 from each side

3x+1-1 ≥4-1

 3x ≥3

Divide by 3

3x/3 ≥3/3

x≥1

So we have

x  ≤-1/2 or x≥1

see attached

Notice closed circles where there is a greater than equal to  or less than equal to