Answer:
The measure of ∠EFG is 52°
Step-by-step explanation:
Given line m is parallel to line p. m∠HEF = 39º and m∠IGF = 13º.we have to find m∠EFG.
In ΔJFG,
By angle sum property of triangle, which states that sum of all angles of triangle is 180°
m∠FJG+m∠JGF+m∠JFG=180°
⇒ 39°+13°+m∠JFG=180°
⇒ m∠JFG=180°-39°-13°=128°
As JFE is a straight line ∴ ∠JFG and ∠EFG forms linear pair
⇒ m∠JFG+m∠EFG=180°
⇒ 128°+m∠EFG=180°
⇒ m∠EFG=52°
The measure of ∠EFG is 52°
It appears as if 12cm is half the length of the side so we can assume that the total length of one side is 24cm.
The area of a square is given by the equation 
where s is the length of the side.
A=576
The area of this square is 576cm2.
Hope this helps!
Area of the shaded region=area of the greater rectangle- area of the inner rectangle.
Area of a rectangle=length x width.
Area of the greater rectangle=(8x-1)(6x)
area of the inner rectangle=(5x+3)(2x)
Area of the shaded region=(8x-1)(6x)-(5x+3)(2x)
=48x²-6x-(10x²+6x)
=48x²-6x-10x²-6x
=38x²-12x
Answer: the area of the shaded region would be: 38x²-12x
What do you need help with?
Answer:
A=72
Step-by-step explanation:
72-2/7 = 10
72-2=70
7X10=70
