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nata0808 [166]
3 years ago
14

Se the given length and area of a rectangle to express the width algebraically.

Mathematics
1 answer:
kifflom [539]3 years ago
7 0
Factor the area polynomial into (2x - 1) and (x + 5)

length is (x + 5) and area is found by multiplying length and width, so the width is (2x - 1) as it's the other factor of the area polynomial after factoring
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Step-by-step explanation:

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4 years ago
The sum of the cube of a number and 12
Black_prince [1.1K]
Let the "number" be n.

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3 years ago
If EF = 2x+13, FG = 20, and EG = 71 what's the value of x​
klemol [59]

Answer:

<h2>x = 19</h2><h2></h2>

Step-by-step explanation:

|<----------------- 71 ----------------------->|

E-----------------------F---------------------G

       2x + 13                 20

find: x

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4 0
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Complete the square to the problem X^2+6x-16=0
marishachu [46]

Answer:

<h2>x = -8 or x = 2</h2>

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\-------------------------------\\\\x^2+6x-16=0\qquad\text{add 16 to both sides}\\\\x^2+6x=16\\\\x^2+2(x)(3)=16\qquad\text{add}\ 3^2\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=16+3^2\\\\(x+3)^2=16+9\\\\(x+3)^2=25\Rightarrow x+3=\pm\sqrt{25}\\\\x+3=-5\ \vee\ x+3=5\qquad\text{subtract 3 from both sides}\\\\\boxed{x=-8\ \vee\ x=2}

3 0
4 years ago
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