All categories

2 years ago

Juanita is booking a 4-night stay at a hotel. The rate is $79 per room plus tax.

1 answer:

3 0

Answer: you don’t specify if it’s $79 per night or $79 for all 4 nights, so i’ll give you 2 answers.

if it’s $79 per night, then the answer is $344.44

if it’s $79 for all 4 nights, then the answer is $86.11

You might be interested in

Use the discriminant to describe the roots of each equation. Then select the best description,

mr Goodwill [35]

$\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{6}x^2\stackrel{\stackrel{b}{\downarrow }}{+13}x\stackrel{\stackrel{c}{\downarrow }}{+6}=0 ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{one solution}\\ \underline{positive}&\textit{two solutions}\qquad \textit{\Large \checkmark}\\ negative&\textit{no solution} \end{cases} \\\\\\ 13^2-4(6)(6)\implies 169-144\implies 25$

6 0

3 years ago

If a bag contains 12 quarters, 6 dimes, and 18 nickles, what is the part-to-whole ratio of quarters to all coins?

d1i1m1o1n [39]

12:36 (12 quarters +6 dimes +18 nickles = 36 coins in total.)
So ... 12/12 = 1 , 36/12 = 3
So the answer is B.) 1:3

4 0

2 years ago

Read 2 more answers

Match the confidence level with the confidence interval for the population mean. type the correct letter in each box. equation e

Ainat [17]

Answer:

$\bar X \pm 1.96 \frac{\sigma}{\sqrt{n}}$

"=1-2*(1-NORM.DIST(1.96,0,1,TRUE))"

And we got 95%

$\bar X \pm 1.645 \frac{\sigma}{\sqrt{n}}$

"=1-2*(1-NORM.DIST(1.645,0,1,TRUE))"

And we got 90%

$\bar X \pm 2.575 \frac{\sigma}{\sqrt{n}}$

"=1-2*(1-NORM.DIST(2.575,0,1,TRUE))"

And we got 99%

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case we have the following cases:

$\bar X \pm 1.96 \frac{\sigma}{\sqrt{n}}$

And for this case we can find the % of confidence with the following excel code:

"=1-2*(1-NORM.DIST(1.96,0,1,TRUE))"

And we got 95%

For the other case:

$\bar X \pm 1.645 \frac{\sigma}{\sqrt{n}}$

And for this case we can find the % of confidence with the following excel code:

"=1-2*(1-NORM.DIST(1.645,0,1,TRUE))"

And we got 90%

For the other case:

$\bar X \pm 2.575 \frac{\sigma}{\sqrt{n}}$

And for this case we can find the % of confidence with the following excel code:

"=1-2*(1-NORM.DIST(2.575,0,1,TRUE))"

And we got 99%

8 0

3 years ago

How do I rotate a point by 180 degrees clockwise?

gizmo_the_mogwai [7]

180 degrees is half of a circle, and clockwise means turning in the direction a clock does - right.

So a point would be turned right halfway around.

8 0

3 years ago

Please solve in the next 10 minutes pleaseeee

Alex787 [66]

Answer:

43.82 mph

266.67 feet

Step-by-step explanation:

Given :

S = √30fl

S = speed of car

f = drag Coefficient

l = Length of skid mark

If f = 0.8 ; l = 80 feets

s = √30fl

s = √(30*0.8*80)

s = √1920

s = 43.817

s = 43.82 mph

B.)

s = 80 mph

f = 0.8

s = √30fl

80 = √30*0.8*l

80 = √24l

Square both sides

80² = 24l

6400 = 24l

l = 6400/24

l = 266.67 feets

6 0

2 years ago