Question

For align="absmiddle" class="latex-formula"> and (x) = $g(x)= x^{2} -5,$ find $(\frac{g}{f}) (x)$
A. $\frac{x^{2} - 5 }{4x +1 },x$ ≠ $-\frac{1}{4}$


B. x$\frac{4 x +1 }{x^{2} - 5}, x$ ≠ ± $\sqrt[]{5}$


C. $\frac{4x +1}{x^{2} -5}$


D.$\frac{x^{2} -5 }{4x + 1}$

Answer 1

Answer is C
Answer is C
Answer is C

Answer 2

The answer would be C.