Answer: 85.62 L represents volume (V).
Explanation:
Volume is defined as the amount or quantity of a given substance or an object.
According to ideal gas equation:

P = pressure of gas = 4.95 atm
V = Volume of gas = 85.62 L
n = number of moles
R = gas constant =
T =temperature =
Thus 85.62 L represents volume (V).
LiAlH₄ is used as strong reducing agent. The hydride produced acts as a nucleophile and attacks the electrophillic carbon of carbonyl group. In given example two reactions are observed.
Reaction 1: In first step LiAlH₄ when treated with
Ester produces corresponding
Aldehyde and alcohol.
Reaction 2: This aldehyde produced further reacts with LiAlH₄ to give a reduced product (
Alcohols). In this case Butanol is produced.
The reaction schemes are shown as felow,
Explanation:
To balance a chemical equation, there are so many approaches to solve the problem.
A balanced chemical equation is one that obeys the law of conservation of matter.
According to this law "matter is neither created nor destroyed by atoms are just rearranged in chemical reaction".
This implies implies that equal number of atoms must be on both sides of the equation.
There are two main approaches to balancing chemical equation;
- Inspection
- mathematical equation
We can inspect the equation and affix the proper coefficients to combining species.
Mathematically, we establish simple solvable algebraic equations to find the number of respective coefficients that will balance the equation:
For example:
H₂ + O₂ → H₂O
mathematically;
aH₂ + bO₂ → cH₂O
conserving:
H : 2a = 2c
O: 2b = c
let a = 1
c = 1
b = 
multiply by 2 to give;
a = 2, b = 1 , c= 2
2H₂ + O₂ → 2H₂O
learn more:
Balanced equation brainly.com/question/9325293
#learnwithBrainly
Patent - Not sure if this is much of a Chem question dou.
Answer:
24 g of C are needed to produce 1mol of CH₄
Explanation:
The reaction is:
2C (s) + 2H2O (l) → CH4(g) + CO2 (g)
2 moles of carbon react with 2 moles of water in order to produce 1 mol of methane and 1 mol of carbon dioxide.
If we want to produce 1 mol of methane, we need 2 moles of C
Let's find out the mass → 2 mol . 12 g/1 mol = 24g