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4 years ago

10

A fish tank holds 10450ml of water. The water is leaking at a rate of 270ml per minute. What is the function to model this situa

tion.

1 answer:

bogdanovich [222]4 years ago

3 0

Answer:

The function is given f(t) = 10450 - 270t

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Write the equation in standard form for the circle that has a diameter with endpoints (- 1, 12) and (- 1, 8)

matrenka [14]

Answer:

The equation in standard form is $(x + 1)^{2} + (y - 10)^{2} = 4$

Step-by-step explanation:

The distance from (-1, 12) to (-1, 8) = 4 = diameter of the circle. So, 2 = radius

The center of the circle is at (-1, 10)

The equation in standard form is $(x + 1)^{2} + (y - 10)^{2} = 4$

3 0

3 years ago

Please help I’m honestly gonna cry lol

BARSIC [14]

Answer: 2z-15

Step-by-step explanation

Based on the visual image, AD is a line where a point O intersects somewhere on the line. AD is represented as 3z-11, while the segment from AO is represented as z+4.

In order to find the answer, we must subtract the entire line (AD) from AO in order to find the missing segment OD.

AD - AO = OD

(3z-11) - (z+4) = OD

Distribute the negative sign so it becomes:

(3z-11) -z - 4 = OD

Now combine like terms.

(3z-z) +(- 11 -4)= OD

2z - 15 = OD

And that is your answer!

6 0

2 years ago

The shelter has 90 dogs and 150 cats. of these animals 9 dogs and 27 cats receive medication. What percentage of animals receive

krek1111 [17]

3% because If you divide 27/9

4 0

3 years ago

Help me with this question plz?

wel

Volume of cylinder = πr²h = π x 4² x 6 = 96π

volume of cone = 1/3πR²H = 1/3π x 8² x 12 = 256π

You can see that volume of cone is more than twice of volume of cylinder. So she is not correct

8 0

3 years ago

This is Matrix for pre calc

gavmur [86]

The given system of equations in augmented matrix form is

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]$

If you need to solve this, first get the matrix in RREF:

Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]$

Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]$

Add 164(row 3) to -91(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]$

Multiply row 4 by 1/13080:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]$

Add -153(row 4) to row 3:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]$

Multiply row 3 by -1/91:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add 6(row 3) and -8(row 4) to row 2:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 2 by 1/5:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

$\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 1 by 1/3:

$\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

So the solution to this system is $(w,x,y,z)=(1,-2,4,-3)$ .

6 0

3 years ago