Another way to solve this is to use the Midpoint Formula. The midpoint of a segment joining points

and

is

So the midpoint of your segment is

Perhaps it helps to see that the x-coordinate of the midpoint is just the average of the x-coordinates of the points. Ditto for the y-coordinate of the midpoint; just average the y's.
Answer:
What about
Step-by-step explanation:
SUS :0000
jp I'm pretty sure its asa. forgive me if im wrong.
Answer:
DC = 2
Step-by-step explanation:
The wrong equation was used.
The right equation to use based on the midsegment theorem of a trapezoid is:
MN = ½(AB + DC)
MN = 8
AB = 14
Substitute
8 = ½(14 + DC)
Multiply both sides by 2
8*2 = ½(14 + DC)*2
2*8 = 14 + DC
16 = 14 + DC
16 - 14 = 14 + DC - 14
2 = DC
DC = 2
Answer:
a. 
b. x ≠ -5 (Vertical asymptote) and x ≠ 5 (Hole)
Step-by-step explanation:
Factor the numerator (Grouping):
Two numbers that multiply to -30 and add to -7 = -3 and 10
![[2x^2 - 10x] + [3x - 15]](https://tex.z-dn.net/?f=%5B2x%5E2%20-%2010x%5D%20%2B%20%5B3x%20-%2015%5D)

Factor the denominator (Difference of Two Squares):
= 
Factored Expression:
(x - 5) can be factored out of top and bottom as a hole-

Variable Restrictions:
Denominator ≠ 0

Vertical asymptote at x = -5 ⇒ x ≠ -5