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9966 [12]
3 years ago
9

2. You are making necklaces for your friends. You have 72 blue beads and 42 red beads. Each friend will receive an identical nec

klace, and all beads must be used
Mathematics
1 answer:
hoa [83]3 years ago
4 0
To find out the number of necklaces that can be made from 72 and 42 beads, think of the Greatest Common Factor of both numbers

Factors of 72
1 × 72
2 × 36 
3 × 24
4 × 18
6 × 12
8 × 9

Factors of 42
1 × 42
2 × 21 
3 × 14
6 × 7

The Greatest Common Factor is 6, so there are 6 necklaces can be made with equal number of beads
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What is the volume of the prism?
jok3333 [9.3K]

Answer:

78.75 cm³

Step-by-step explanation:

Volume = Width × Height × Length

V = 5 × 4.5 × 3.5

V = 78.75 cm³

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3 years ago
What is the variables on both sides equations? 3x - 6 = 7x + 1​
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Answer:

3x-6=7x+1

=> 3x-7x = 6+1

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3 years ago
What value of x makes this equation true?
m_a_m_a [10]
2(2)-3=5-2(2)
4-3=5-4
1=1

The correct answer is A
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3 years ago
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In a certain county, the number of charter schools is 6 less than twice the number of alternative schools. We know that there ar
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2x-6=52                               x= alternative schools
2x=58
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83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi
arlik [135]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

Step-by-step explanation:

Information given

\bar X=32.1 represent the sample mean

\mu population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom given by:

df=n-1=8-1=7

The confidence level is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,82)" "=CHISQ.INV(0.95,82)". so for this case the critical values are:

\chi^2_{\alpha/2}=104.139

\chi^2_{1- \alpha/2}=62.132

The confidence interval is given by:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

5 0
3 years ago
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