Well...this is a proportion problwm. for every 16 cups I have 1 gallon, so I can write that as:
16 cups
-----------
1 gallon
this value will be proportional to 1/4 a gallon equal "so many" cups. let's equal the unknown about of cups to x.
16 cups______ x cups
-----------.... = ..... ----------
1 gallon _____ 1/4 gallons
I can cross multiply to find x.
1 gallon • x cups = 16 cups • 1/4 gallons
16 times 1/4 is the same as 16/4, which equals 4.
1 gallon • x cups = 4 cups gallons
divide both sides by gallons
x cups = 4 cups
so! 1/4 of a gallon equals 4 cups.
Y-2= -3/4(x-6)
y=-3/4(x-6)+2
y=-3/4x+9/2+2
y=-3/4x+13/2
so for example if x=1 then y=5.76
or if x= 5 then y=2.75
~(-19,32)
Equation form x=-19,y=32
Answer:
I love turtles I used to have one
Answer:
(m³/3 + 5m/2 + 3)pi
Step-by-step explanation:
pi integral [(f(x))² - (g(x))²]
Limits 0 to 1
pi × integral [(2+mx)² - (1-mx)²]
pi × integral[4 + 4mx + m²x² - 1 + 2mx - m²x²]
pi × integral [m²x² + 5mx + 3]
pi × [m²x³/3 + 5mx²/2 + 3x]
Upper limit - lower limit
pi × [m²/3 + 5m/2 + 3]
Verification:
m = 0
[pi × 2² × 1] - [pi × 1² × 1] = 3pi
[m³/3 + 5m/2 + 3]pi
m = 0
3pi
