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Andreyy89
3 years ago
10

ralph is three times as old as sarah. in 6 years ralph will be twic as od as sarah will be then find ralphs age now

Mathematics
1 answer:
frutty [35]3 years ago
8 0
1) 3S = R 2) R+6= 2 (S+6)= 2S+12 ----> R=2S+61,2 )--> 3S = 2S+6 ---><span>S=6 & R= 3 x 6 = 18Ralph is 18 & Sara is 6 .</span>
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Solve the system using elimination.
KIM [24]
We can't eliminate as is so we have to change something up there in the equations to get either the x values the same number but opposite signs, or the y values the same number but opposite signs.  I chose to change the y values to the same number but different signs. In the first equation y is -3y and in the second one, y is -8y. The LCM of both of those numbers is 24, so we will multiply the first equation by an 8 (8*3=24) and the second equation by 3 (3*8=24) but since they are both negative right now, one of those multiplications has to involve a negative because - * - = +. Set it up like this:
8(-10x - 3y = -18)
-3(-7x - 8y = 11)
Multiply both of those all the way through to get new equations:
-80x - 24y = -144
 21x  +24y = -33
Now the y's cancel each other out leaving only the x's:
-59x = -177 and x = 3.  Now plug that 3 into either one of the original equations to find the y value.  Either equation will work; you'll get the same answer using either one. Promise. -7(3) - 8y = 11 gives a y value of -4.  so your solution is (3, -4) or B above.
7 0
3 years ago
Read 2 more answers
One positive number is 14 less than another positive number. If the reciprocal of the smaller number is added to five times the
Kipish [7]

Let's call the two numbers s and l.


Given these variables, we can say: s = l - 14, based on the first sentence in the problem.


Also, remember that the reciprocal of a number is simply 1 divided by the number. Thus, we can say that:

\dfrac{1}{s} + 5\Big( \dfrac{1}{l} \Big) = \dfrac{1}{4}


To solve, we can simply substitute l -14 in for s in the second equation and solve.

\dfrac{1}{l - 14} + \dfrac{5}{l} = \dfrac{1}{4}

  • Set up

\dfrac{l}{l(l - 14)} + \dfrac{5(l - 14)}{l(l - 14)} = \dfrac{1}{4}

  • Get terms on the left side to a common denominator for easier addition

\dfrac{l + 5l - 70}{l(l - 14)} = \dfrac{1}{4}

  • Simplify

4(6l - 70) = l(l - 14)

  • Cross multiplication (\frac{a}{b} = \frac{c}{d} \Rightarrow ad = bc)

24l - 280 = l^2 - 14l

  • Simplify

l^2 - 38l + 280 = 0

  • Subtract 24l - 280 from both sides of the equation

(l - 10)(l - 28) = 0

  • Factor left side of the equation

l = 10, 28

  • Zero Product Property

Now, notice that we have found two solutions, but the problem is only asking for one. This <em>likely </em>means that one of our solutions is extraneous. Let's take a look. Remember that the smaller positive number is equal to 14 less than the larger number. However,

s = 10 - 14 = -4,

Since s is not positive in this case, l = 10 is not a solution.


Thus, l = 28 is our only solution. In this case,

s = 28 - 14 = 14,

which means that the smaller number is 14 and the larger number is 28.

5 0
3 years ago
682 rounded to the nearest hundred
defon
700, because 8 is 5 and up so it'll be rounded up.
4 0
3 years ago
Read 2 more answers
For which equation does it make the most sense to solve by using the square root property?
ziro4ka [17]
Just took the test, the answer is C.
:)
8 0
3 years ago
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Use the graph to determine the vertex point of the quadratic function. Is the vertex a
Feliz [49]

Answer:

B) Vertex (1,2), maximum

Step-by-step explanation:

First, determine if the graph has a maximum or a minimum value. Since the graph opens downwards, it has a <u>maximum</u> value.

The maximum is the point that has the greatest y value. We can see that the greatest y value is at y=2. Going down two units from that spot, we can see that the x value is at x=1. We can plug those into the vertex form, (x,y). By plugging in we get the point (1,2).

5 0
2 years ago
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