Check the one-sided limits:


If <em>f(x)</em> is to be continuous at <em>x</em> = 5, then these two limits should have the same value, which means
5<em>k</em> = 200
<em>k</em> = 200/5
<em>k</em> = 40
x^2+6x-5=0
x^2=2x
2x+6x-5=0
2x+6x=8x
8x-5=0
+5 +5
(if you don’t know what I’m doing here is that I’m removing the negative 5 by putting a positive 5 since both of them make 0. Also the “x” always stay alone and the unit stays as the unit)
(I putted the positive under the 0 because what u do to the unit you need to do the same thing with the other.)
8x/8=5/8
(If ur lost here it means dividing.)
The answer
X=0.625
(btw I’m not really sure if this is right so um don’t really trust me in this lol)
Answer:
Step-by-step explanation:
bsahaahaaana
The price of this more expensive book was $90.00 ($150 - $60) based on the date acquired from the question above. This problem can be solved using a simple algebra equation which consisted of one variable. The equation is stated as $150 = x + 1.5x (x = $150/2.5 = $60) where x is the price of the cheaper book and 1.5x is the price of the more expensive books because it has 50% higher price than the cheaper book<span>.</span>