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stiv31 [10]
3 years ago
12

1(3/11-7d/17) using distributive property

Mathematics
1 answer:
nadezda [96]3 years ago
6 0
D=51/77
First set up the equation equal to zero(0), the distribute from there.
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Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

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3 years ago
Could someone please solve these for me? Thanks in advance!
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PLEASE HELP!!!!!!!!! 100 POINTS !!!!!!!!!!
schepotkina [342]

Answer:

the answer is 5/6

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
How do I factor the equation in writing this question?
SCORPION-xisa [38]

Step-by-step explanation:

You are just replacing the 'n' with the number in the 'n box'.

So if this is the formula:

b(n) = 4 - (n \div 3)

then:

B(-3)= 4-(-3/3)

B(-3)= 4-( -1)

B(-3)= 4+1

B(-3)= 5

B(0)= 4-(0/3)

B(0)= 4-0

B(0)= 4

B(3)= 4-(3/3)

B(3)= 4-1

B(3)= 3

6 0
3 years ago
Find the slope and the y-intercept of the equation: 6y - 3x= -12
vivado [14]
Slope can be found but putting the equation in slope intercept form (y=mx+b)

6y=3x-12
y= 0.5x-2

M is your slope, b is the y intercept.

So the slope is 1/2, yintercept is (0,-2)

Hope this helps
7 0
3 years ago
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