Answer:
w>-5/12
Step-by-step explanation:
w > 1/3 - 3/4 = 4/ 12 - 9/ 12
w> -5/12
Remark
I think you want us to do both 3 and 4
Three
QR is 4 points going left from the y axis + 2 points going right from the y axis.
QR = 6 units long.
RT is 4 units above the x axis and 3 units below the x axis
RT = 7 units long
TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.
Problem 4
You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.
Area = (b1 + b2)*h/2
Givens
B1 = QR = 6
B2 = UT + TS = 6 + 3 = 9
h = RT = 7
Area
Area = (6 + 9)*7/2
Area = 15 * 7 / 2
Area = 52.5
Comment
You could break this up into a rectangle + a triangle
Find the area of QRTU and add the Area of triangle RTS
<em>Area of the rectangle </em>= L * W
L = RT = 7
W = QR = 6
Area = 7 *6 = 42
<em>Area of the triangle</em> = 1/2 * B * H
B = TS = 3
H = RT =7
Area = 1/2 * 3 * 7
Area = 1/2 * 21
Area = 10.5
Total Area = 42 + 10.5 = 52.5 Both answers agree.
Answer:
1. area of new pen = 11 
2. i. 5 feet by 2 feet
ii. 2 ½ feet by 4 ½ feet
Step-by-step explanation:
The size of the pen as planned = 5 ft long by 4 ½ ft wide
Area of the pen = length x width
= 5 x 4 ½
= 5 x 
Area of the pen = 
= 22 ½
But, Krista has to make the pen ½ the size of planned. So that;
area of new pen = ½ x 22 ½
= ½ x
= 
= 11
area of new pen = 11
The area of the new pen would be 11 .
The possible values she could use are:
i. 5 feet by 2 feet
ii. 2 ½ feet by 4 ½ feet
Hello :
y exist : x+6 <span>≥ 0
x </span>≥ -6
