Hello,
Answer A: no solution
line 1: (-6,3), (3,6)==>y-3=(x+6)*3/9==>x-3y=-15 (1)
line 2: (-3,1), (3,3)==>y-1=(x+3)2/6==> x-3y=-6 (2)
(1)-(2)==>0x=-9 ==> no solution
line 1 // line 2
Answer:
242
Step-by-step explanation:
Simplify the following:
11 ((9^2 - 5^2)/2^2 + 8)
Hint: | Evaluate 2^2.
2^2 = 4:
11 ((9^2 - 5^2)/4 + 8)
Hint: | Evaluate 5^2.
5^2 = 25:
11 ((9^2 - 25)/4 + 8)
Hint: | Evaluate 9^2.
9^2 = 81:
11 ((81 - 25)/4 + 8)
Hint: | Subtract 25 from 81.
| 7 | 11
| 8 | 1
- | 2 | 5
| 5 | 6:
11 (56/4 + 8)
Hint: | Reduce 56/4 to lowest terms. Start by finding the GCD of 56 and 4.
The gcd of 56 and 4 is 4, so 56/4 = (4×14)/(4×1) = 4/4×14 = 14:
11 (14 + 8)
Hint: | Evaluate 14 + 8 using long addition.
| 1 |
| 1 | 4
+ | | 8
| 2 | 2:
11×22
Hint: | Multiply 11 and 22 together.
| 2 | 2
× | 1 | 1
| 2 | 2
2 | 2 | 0
2 | 4 | 2:
Answer: 242
Answer:
2.50*146=365
Step-by-step explanation:
The answer is 1 yr
The first one because if you add all the positives you get 4 and then if you add all the negatives you get 7 so then you do 4+(-7)= -3
There you go. cube root of smth is just the value to the power of one third.
