We can use Pythagorean's Theorem in order to find the remaining side length
a^2+b^2=c^2
Let a be the shadow length
Let b be the height of the flagpole
Let c be the hypotenuse
28^2+b^2=35^2
784+b^2=1225
b^2=1225-784
b^2=441
b=√441
b=21
Therefore the flagpole is 21 meters tall.
Hope this helps!
(-y + 5a - 4) + (3y - a - 5) is simplified to 2y + 4a - 11
Answer:
The answer would be 50
Step-by-step explanation:
Answer:
No solution
Step-by-step explanation:
3x - 2= 3x + 5
3x is canceled out so
- 2 ≠ 5
No solution
Answer:
The correct option is;
Yes, his calculations are correct and the volumes for figures are equal
Step-by-step explanation:
The volume, V, of a square (of side s) pyramid of height h = 
Where:
s = 9.7 inches
h = 9 inches
We have;
The volume, 
, of a cylinder of radius r = Base area × Height, h = (π×r²)×h
Where:
Base area = π×r²
r = Radius of the cylinder = 5.47 inches
h = Height of the cylinder = 3 inches
= π × 5.47² × 3 = π × 29.9209 × 3 = π × 89.7627 = 281.998 ≈ 282 m³
Therefore, Jude is correct.
