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topjm [15]
3 years ago
12

Find the solution to the equation graphically. 10x-10= x+10

Mathematics
1 answer:
vova2212 [387]3 years ago
7 0

Answer:

100/9

Step-by-step explanation:

here is thd answer

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Answer:a

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Find the sum of 2 • 3 and 2 • x to determine which expression is equal to 2(3 + x).
zalisa [80]

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6+2x is the answer

Step-by-step explanation:

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Help please I need this now
professor190 [17]

Answer:

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Step-by-step explanation:

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BRAINLIESTT ASAP! PLEASE HELP ME :)
Maslowich

Step-by-step explanation:

\displaystyle y = Asin(Bx - C) + D

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{\frac{1}{7}} = 0 \\ Period → \frac{2}{1}π = 2π

Therefore we have our answer.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|

NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is.

I am joyous to assist you anytime.

3 0
3 years ago
22. Mona is in her garden jumping on stones (as shown below).
iris [78.8K]

\large\green{\sf\boxed{Given:-}}

<u>Mona starts from 68th stone</u>

<u>She jumps</u><u> </u><u>23</u><u> </u><u>stones</u><u> </u><u>ahead</u><u> </u>

<u>Then</u><u> </u><u>she</u><u> </u><u>jumps</u><u> </u><u>28</u><u> </u><u>stones</u><u> </u><u>back</u>

\large\red{\sf\boxed{To \:find:-}}

<em>Her final position=?</em>

\large{|\underline{\mathtt{\red{S}\blue{o}\orange{l}\pink{u}\blue{t}\purple{i}\green{o}\red{n}\blue{:}\orange{-}}}}

  • Add 23 in 68 [Given]

\begin{gathered}\\ \sf\longmapsto 68+23=91\end{gathered}

  • Subtract 28 from 91

\begin{gathered}\\ \sf\longmapsto 91-28=Her\:final\:position\end{gathered}

\begin{gathered}\\ \sf\longmapsto =63\end{gathered}

  • To find how much stones she is ahead or back we will Subtract 63 from 68 which was her initial position.

\begin{gathered}\\ \sf\longmapsto 68-63=5\end{gathered}

So, Mona will be <em><u>5</u></em><em><u> </u></em><em><u>stones</u></em><em><u> </u></em><em><u>behind</u></em><em><u> </u></em><em><u>from</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>starting</u></em><em><u> </u></em><em><u>stone</u></em><em><u>.</u></em>

☯️Hence, Option C is correct

7 0
2 years ago
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