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lara31 [8.8K]
3 years ago
5

a fair die is cast four times. Calculate the probability of obtaining exactly two 6's round to the nearest tenth of a percent

Mathematics
1 answer:
Mrac [35]3 years ago
6 0

|\Omega|=6^4=1296\\|A|=1\cdot1\cdot5\cdot5\cdot\dfrac{4!}{2!2!}=25\cdot6=150\\\\P(A)=\dfrac{150}{1296}\approx11.6\%

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