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sveticcg [70]
4 years ago
13

What is tangent of 52?

Mathematics
2 answers:
Wewaii [24]4 years ago
5 0
9 is the tangent of 52
snow_lady [41]4 years ago
3 0
1.27994 is the decimal forum
You might be interested in
The sum of three consecutive odd numbers is 183. What is the second number in the sequence?
atroni [7]

Answer:

61

Step-by-step explanation:

If you want only the middle number, then call it x

the largest of the 3 is x + 1

The smallest of the 3 is x - 1

Add

x + 1 + x - 1 + x = 183 Cancel the 1s out.

x + x + x  = 183          Combine the like terms on the left

3x = 183                     Divide by 3

x = 183/3                    Do the division

x = 61

The middle number is 61

5 0
3 years ago
Find the point(s) on the surface z^2 = xy 1 which are closest to the point (7, 11, 0)
leonid [27]
Let P=(x,y,z) be an arbitrary point on the surface. The distance between P and the given point (7,11,0) is given by the function

d(x,y,z)=\sqrt{(x-7)^2+(y-11)^2+z^2}

Note that f(x) and f(x)^2 attain their extrema, if they have any, at the same values of x. This allows us to consider the modified distance function,

d^*(x,y,z)=(x-7)^2+(y-11)^2+z^2

So now you're minimizing d^*(x,y,z) subject to the constraint z^2=xy. This is a perfect candidate for applying the method of Lagrange multipliers.

The Lagrangian in this case would be

\mathcal L(x,y,z,\lambda)=d^*(x,y,z)+\lambda(z^2-xy)

which has partial derivatives

\begin{cases}\dfrac{\mathrm d\mathcal L}{\mathrm dx}=2(x-7)-\lambda y\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dy}=2(y-11)-\lambda x\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dz}=2z+2\lambda z\\\\\dfrac{\mathrm d\mathcal L}{\mathrm d\lambda}=z^2-xy\end{cases}

Setting all four equation equal to 0, you find from the third equation that either z=0 or \lambda=-1. In the first case, you arrive at a possible critical point of (0,0,0). In the second, plugging \lambda=-1 into the first two equations gives

\begin{cases}2(x-7)+y=0\\2(y-11)+x=0\end{cases}\implies\begin{cases}2x+y=14\\x+2y=22\end{cases}\implies x=2,y=10

and plugging these into the last equation gives

z^2=20\implies z=\pm\sqrt{20}=\pm2\sqrt5

So you have three potential points to check: (0,0,0), (2,10,2\sqrt5), and (2,10,-2\sqrt5). Evaluating either distance function (I use d^*), you find that

d^*(0,0,0)=170
d^*(2,10,2\sqrt5)=46
d^*(2,10,-2\sqrt5)=46

So the two points on the surface z^2=xy closest to the point (7,11,0) are (2,10,\pm2\sqrt5).
5 0
4 years ago
Solve this system of equations using substitution:
irina [24]
The substitution method means you replace the variable in one equation with the other equation, so your new equation is x+4x-8=10. Add 10 to both sides to get 5x=18. Divide both sides by 5 to get x=3.6. This is a weird equation, but then to get y, work backwords. 3.6 times 2=7.2. 7.2-4=3.2 y=3.2. Finally to finish checking solve the equation as normal. 3.6+6.4=10. I hope this helped! Please give brainliest!
Your final answer is x=3.6 y=3.2
3 0
3 years ago
How do I solve 3 (9-5)² ÷8 ?
Harrizon [31]

Answer:

3(9-5)^2 ÷8

3(4)^2÷8

3(16)÷8

3(2)=6

8 0
4 years ago
Read 2 more answers
Can someone pleaseeee help and if you’re correct I’ll give u brainlist
Dmitry [639]

Answer:

i believe its b but its kind of hard to read

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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