The amount of rim needed for each window is 141.4 in
<h3>How to find the length of the outer rim?</h3>
Since the outer rim is the length of an arc, we use the formula for length of an arc of a circle.
<h3>What is an arc?</h3>
An arc is part of section of the circumference of a circle
<h3>What is the length of an arc?</h3>
So, length of arc, L = Ф/360 × 2πR where
- Ф = central angle of arc and
- R = radius of circle.
Gven that for the window rim
- Ф = angle of the rim = 270° and
- R = radius of the rim = 30 in
Substituting the values of the variables into the equation for L, we have
L = Ф/360 × 2πR
L = 270°/360° × 2π × 30 in
L = 3/4 × 2π × 30 in
L = 3/2 × π × 30 in
L = 3 × π × 15 in
L = 45π in
L = 141.37 in
L ≅ 141.4 in
So, the amount of rim needed for each window is 141.4 in
Learn more about length of an arc here:
brainly.com/question/8402454
#SPJ1
Answer:
2
Step-by-step explanation
Either your 5, your just trying brain.ly out, or your trolling don't care either way
What the make no sense but I believe it is 50.24 hope that helps
Begin by finding the lowest point the quadratic equation can be, the vertex;
x²-1= is just a translation down of the graph x²
vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}.
For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers.
Hope I helped :)
