Multiply. (5x^2-6x+2)(4x^2-3x)

One-half a number minus 6 is 4. what is the number

tatyana61 [14]

Answer:

the answer is 20

Step-by-step explanation:

20/2= 10. 10-6= 4.

8 0

3 years ago

Anya's grandparents decide they want to invest at the bank. They have $35,000

Aneli [31]

Anya's parents will have $44,440.71 after 6 years if they invested in a bank.

The interest rate given is an annual rate yet will be compounded quarterly. You therefore need to convert the interest rate to a quarterly rate.

= 4% / 4 quarters

= 1% per quarter

Number of periods:

= Number of years x Number of quarters in year

= 6 x 4

= 24 quarters

The amount they will have in their account is:

<em>= Amount x ( 1 + rate) ^ number of periods </em>

= 35,000 x ( 1 + 1%)²⁴

= $44,440.71

In conclusion, they will have $44,440.71 if they invested their money in a bank for 6 years.

<em>Find out more at brainly.com/question/13861384.</em>

3 0

2 years ago

Jan'ai was asked to determine the minimum for a function with zeros located at –1 and 5, which also has a y-intercept of (0, –25

sergey [27]

The first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

<h3>What are the coordinates of vertex for a quadratic function?</h3>

For a quadratic function of the form $y = ax^2 + bx + c$ , its vertex form is obtained as:

$y = ax^2 + bx + c\\y =a(x^2 + bx/a) + c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2 -(b/2a)^2 )+ c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2) -a \times (b/2a)^2 + c\\\\y = a(x+b/2a)^2 - a \times (b/2a)^2 + c$

For the form $y = a(x-h)^2 + k$ , the vertex has coordinates (h, k)

Thus, for the obtained equation $y = a(x+b/2a)^2 - a \times (b/2a)^2 + c$ , we get the coordinates of vertex as:

$h = -b/2a$ , $k = c - a\times(b/2a)^2$

Thus, the coordinates of vertex of $y = ax^2 + bx + c$ is:

$(h,k) = (-b/2a, c - a \times (b/2a)^2 )$

The missing steps of work of Jan'ai are:

Begin to write a function in factored form. $f(x) = a(x+1)(x-5)$
Substitute x = 0, y = f(x) = -25 to determine a. $-25 = a(0+1)(0-5)$
Simplify and solve to find a. $a=5$
Rewrite the function. $f(x) = 5(x+1)(x-5)$
Rewrite in standard form. $f(x) = 5x^2-20x-25$
Find the x-coordinate of the vertex. $x = -20/2(5) = -20/10; x = -2$
Find the y-coordinate of the vertex.

$y = 5x^2-20x-25$

$y = 5(-2)^2-20(-2)-25$

$y = 35$

so (-2,35) is the coordinate of the vertex, which denotes the minimum.

So, as we see, in the 5th step, Jan'ai had the quadratic function $f(x) = 5x^2-20x-25$ ,

Comparing this to $f(x) = ax^2 + bx + c$ , we get a = 5, b = -20, c = -25

The vertex's x-coordinate will be on -b/2a = -(-20)/ 2(5) = 20/10 = 2

But Jan'ai didn't putted that negative sign before b. in the 6th step.

Thus, the first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

Learn more about the vertex form of a quadratic equation here:

brainly.com/question/9912128

6 0

3 years ago

Given that x= -3, what is the value of 2×² - x + 5?

Roman55 [17]

Answer:

26

Step-by-step explanation:

2(9)-(-3)+5

2(9)+3+5

18+8

26

3 0

3 years ago

Read 2 more answers

There are 25 balls in a bag, made up of two different colours,

Sonbull [250]

Answer: The answer would be 13/25

Since there are 25 balls and 12 black balls, you want to subtract 12 from 25 to get the number of blue balls. There are 25 balls in total, so the probability of getting a blue ball is 13/25

6 0

3 years ago