Use distributive property:
16. 5k(3 - 4k)
15k - 20k^2
18. 6g^2(g - 8)
6g^3 - 48g^2
20. -2n^2 (5n - 9 + 4n^2)
-10n^3 + 18n^2 - 8n^4
For this case, the area is given by:
A = x * (200-2x)
Rewriting:
A = 200x-2x ^ 2
Deriving the expression we have:
A '= 200-4x
Equaling zero we have:
200-4x = 0
We clear x:
4x = 200
x = 200/4
x = 50 feet
Then, the maximum area is:
A (50) = 50 * (200-2 * 50)
A (50) = 5000 feet ^ 2
Answer:
the maximum possible area that can be enclosed with his 200ft of fencing is:
A (50) = 5000 feet ^ 2
1 meter = 100 cm
85 cm
1 mm = 0.1 cm, so 400 mm = (400 x 0.1) = 40 cm
100 + 85 + 40 = 225 cm <== total length
Answer: The value of a is -6.
Step-by-step explanation:
To do this we need to find the y-intercept first.
-2= 4(1/2) + b
-2=2+ b
-2 -2
b= -4 so now the y-intercept is -4 so we will now have the equation y= 1/2x -4
so now put -4 into the equation for x and solve for y.
y= 1/2(-4) -4
y = -6
60,000 would be the answer because it stays the same if under 5 it stays if above 5 rounds up once
