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2 years ago

Is X^2-Y^2=0 a quadratic equation ?

2 answers:

8 0

I dont think so but to justify quads means four and the is no sign of x to the fourth power or y to the fourth power ect.

Deffense [45]2 years ago

8 0

No, it's liner function
y=x
(Would be just a straight line the graph, not parabola)

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Order the numbers from least to greatest -1/3, -0.3, 4/3, 1.2, 3/2

Nikolay [14]

Answer:

1/3,-0.3,1.2,4/3,3/2

Step-by-step explanation:

-1/3,-0.3,1.2,4/3,3/2

7 0

2 years ago

A go-cart with a mass of 200 kg is pushed with a force of 1000 N (1000 kg m/s2). What is the acceleration of the go-cart?

Hunter-Best [27]

Answer:

Acceleration=5m/s^2

Step-by-step explanation:

F=ma

1000=200xa

a=1000/200

a=5m/s^2

8 0

2 years ago

Select the correct answer. Jason inherited a piece of land from his great-uncle. Owners in the area claim that there is a 45% ch

GREYUIT [131]

Answer:

Option A 0.1698

Step-by-step explanation:

Given that Jason has a chance for getting oil as 45%

THe kit he buys show accurate result with 80% probability

Let A1- Event that the land has oil

A2 - Event that the land has no oil

B- The test gives negative result

A1 and A2 are mutually exclusive and exhaustive

P(A1) = 0.45 and P(A2) =0.55

Hence we can use Baye theorem

Then P(B) = P(A1B)+P(A2B)= $0.45(0.20)+0.55(0,80)\\=0.09+0.0.44\\=0.53$

Reqd prob =P(A1/B) =

$\frac{P(A1B)}{P(B)}\\ =\frac{0.09}{0.53}\\\\=0.1698$

3 0

2 years ago

In 2000, the total population of the U.S. was 281.4 million people. In 2010, it was 308.7 million people. What is the average ra

kifflom [539]

Answer:

2.73 million people per year

Step-by-step explanation:

Turn sentences into coordinates/points:

In 2000, 281.4 million people

(x₁, y₁) = (2000, 281.4)

In 2010, 308.7 million people

(x₂, y₂) = (2010, 308.7)

Rate of population per year:

$\sf \dfrac{y_2 - y_1}{x_2- x_1} \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points$

$\rightarrow \sf \dfrac{308.7-281.4}{2010-2000}$

$\rightarrow \sf 2.73 \ million \ people$

5 0

1 year ago

Help me out please, im only typing this much because its making me...

Genrish500 [490]

Answer:

B. $x^{2} +2x-8$

Step-by-step explanation:

Here the best method to solve is by substituting the end values of the set in each option , otherwise it will a time consuming problem.

Now substitute x=-4 in all the options

A. $x^{2} -2x-8$

16+8-8=16>0

so out of option A and C option C is correct.

B. $x^{2} +2x-8$

16-8-8=0 which means for the values of x>-4 $x^{2} +2x-8$ is less than 0

Now substitute x=2 in all the options

A. $x^{2} -2x-8$

4-4-8=-8<0 . so option A and C both are incorrect.

B. $x^{2} +2x-8$

4+4-8=0 which means for the values of x<2 $x^{2} +2x-8$ is less than 0

Therefore the correct option is B

6 0

2 years ago