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MA_775_DIABLO [31]
2 years ago
5

Prove that opposite angles of a parallelogram are congruent. Be sure to create and name the appropriate geometric figures.

Mathematics
1 answer:
MatroZZZ [7]2 years ago
7 0
Is there a picture of some sort of angle or parallelogram? Because there isn't enough information to solve the question with only this. Sorry!
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Find the common difference of the arithmetic sequence -19, -16, -13, ...
Yuliya22 [10]

Answer:

d= +3

Step-by-step explanation:

1st term = -19

2nd term = -16

d = 2nd - 1st

d= -16-(-19)

d = +3

4 0
3 years ago
Line l is parallel to line e in the figure below.
dexar [7]

Answer:

? need more info

Step-by-step explanation:

6 0
2 years ago
Solve. Please show your work
Sphinxa [80]

Answer:

128

Step-by-step explanation:

8^2√2^2

64√2^2              rewrite √2^2 as 2

64*2

=128

5 0
3 years ago
What are the equivalent ratios shown in the table? Complete the statement.
Radda [10]
I will !

This is five-fold proportion
The first ratio gives solution namely
We will write general proportion 
a:b= c:d= e:f = g:h= i:j = k
According to this the first ratio gives coefficient k
When we divide 24/2 =12 our coefficient k=12

In the second ratio we will multiply 3 with 12 and get 36.
In the third ratio we will multiplu 5.5 with 12 and get 66.
In the fourth we will divide 108 with 12 and get 9.
In the fifth we will multiply 15 with 12 and get 180.

Finally the ratio is 24:2=36:3=66:5.5=108:9=180:15

Good luck!!!!


6 0
2 years ago
Read 2 more answers
Consider the following. y = x2 y = 20 − x Maple Generated Plot (a) Find the area of the region by integrating with respect to x.
Hunter-Best [27]

Answer:

  area = 121.5

Step-by-step explanation:

See below for a plot and the integral. We assume you are interested in the entire bounded region.

__

  \displaystyle\text{area}=\int_{-5}^4{(20-x-x^2)}\,dx=\left.20x-\dfrac{x^2}{2}-\dfrac{x^3}{3}\right|_{-5}^4\\\\=20(4-(-5))-\dfrac{4^2-(-5)^2}{2}-\dfrac{4^3-(-5)^3}{3}\\\\=180+\dfrac{9}{2}-63=121.5

7 0
3 years ago
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