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aleksley [76]
3 years ago
9

Hey really fast:))) can someone just simplify 3log4x + log4(2-x) - log4(3x), much much appreciated. all i need is work

Mathematics
1 answer:
kirill115 [55]3 years ago
7 0
Try Photomath it’s an app in your phone
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Given that ABCD~JKLM <br> find the ratio of the perimeter of ABCD to JKLM
Westkost [7]

Answer:

The ratio of the perimeter of ABCD to JKLM is;

b. 3/5

Step-by-step explanation:

Given that ABCD ~ JKLM, where;

DC and ML are corresponding sides

AD and JM are corresponding sides

AB and JK are corresponding sides

Therefore;

DC/ML = AD/JM = AB/JK

Plugging in the values of the variables gives;

9/15 = z/10 = x/12

∴ z = 10×9/15 = 6

x = 12×9/15 = 7.2

9/15 = 6/y

y = 6 ×15/9 = 10

The perimeter of the quadrilateral ABCD = AB + BC + DC + AD

∴ The perimeter of the quadrilateral ABCD = 6 + 6 + 9 + 7.2 = 28.2

The perimeter of the quadrilateral JKLM = JK + JM + ML + LK

∴ The perimeter of the quadrilateral JKLM = 12 + 10 + 15 + 10 = 47

The ratio of the perimeter of ABCD to JKLM = 28.2/47 =0.6 = 3/5.

4 0
3 years ago
What is the x-intercept of the group of the function f(x) =x2 -16x + 64
Dimas [21]

The x-intercept of a function is basically it's roots. So when you factor out the function f(x) = x^2 - 16x + 64 you get

(x-8)(x-8)

x = 8

So x-int. is (0,8) or x = 8

3 0
3 years ago
What is the answer for that question please
kicyunya [14]
81 hope it helps you
8 0
3 years ago
Describe in writing how 7/3 compares to 2 1/3
LekaFEV [45]
7/3 IS an improper fraction 2 1/3 is a mixed number
4 0
3 years ago
1)Find the angle of elevation of the sun from the ground when a tree that is
KIM [24]

Answer:

\theta=41.18^{\circ}

Step-by-step explanation:

Given that,

The height of the tree, h = 14 ft

The height of the shadow, b = 16 ft

We need to find the angle of elevation of the sun from the ground. Let the angle be θ. We can use trigonometry to find it. So,

\tan\theta=\dfrac{P}{B}\\\\\tan\theta=\dfrac{14}{16}\\\\\theta=41.18^{\circ}

So, the required angle of elevation of the sun is equal to 41.18^{\circ}.

7 0
3 years ago
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