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PSYCHO15rus [73]
3 years ago
14

Please help asap i have to leave soon

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0
3.5*8=28
The answer is 28 m^3
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Need answer ASAP!!!!!!!!!
seropon [69]
The answer would be x= 7,-7
3 0
3 years ago
Anyoneee help im stuck !! 15 points!!
Gnom [1K]

Answer:

Given: \angle 1, \angle 2, \angle 3, \angle 4 formed by two intersecting segments.

In the given figure;

Linear pair states that a pair adjacent angle formed when two lines intersect.

Then by definition of linear pairs,

\angle 1  and  \angle 2 forms a linear pair

Also,  \angle 2  and  \angle 3 forms a linear pair.

Linear pair postulates states that the two angle that forms a linear pair are supplementary(i,e add up to 180 degree).

Then by linear pair postulates;

m\angle 1+ m\angle 2 =180^{\circ}

and

m\angle 2+m \angle 3 =180^{\circ}

Substitution property of equality states that if x =y then, x can be substituted in for y or vice -versa.

then by substitution property of equality:

m\angle 1+m\angle 2=m\angle 2+ m\angle 3

Addition property of equality states that:

if x =y,  then x + z = y+ z

By addition property of equality:

m\angle 1 =m\angle 3     hence proved!

6 0
3 years ago
Charlotte bought 16 songs for her MP3 player. Three-fourths of the songs are classical songs. How many of the songs are classica
spayn [35]
I think 8 are classical songs
3 0
3 years ago
Read 2 more answers
If 1/6x + 3 = 7 what is x
kotykmax [81]

Answer:

x = 24

Step-by-step explanation:

1/6 x + 3 = 7

1/6 x = 4

x = 24

6 0
3 years ago
Read 2 more answers
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Gre4nikov [31]

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

\frac{200}{60} = \frac{10}{3} \approx  3.33   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

\frac{200}{65} = \frac{40}{13} \approx  3.08   loops per minute

then the period is:

\frac{13}{40} =0.325\,\,\,minutes

Therefore runner B has the smaller period

8 0
3 years ago
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