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3 years ago

What number is missing from the table of equivalent ratios? A) 2 B) 5 C) 7 D) 13 nt

Mathematics

2 answers:

kipiarov [429]3 years ago

6 0

Answer:

The correct answer ir B)5

Step-by-step explanation:

An easy explanation of what a ratio is, is the following:

It is the relationship between two numbers, indicating how many times the first number contains the second.

So, we should divide the first by the second, in all the ratios to know the relation:

3/6=0,5

7/14=0,5

If they are Equivalent that means they all give as a result 0,5.

x/10=0,5

x=0,5*10

x=5 (answer b)

iren [92.7K]3 years ago

3 0

X y
3 6
5 10
7 14 the answer is B

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Number two please ASAP

miv72 [106K]

The solutions for $-5 +2x^{2} = -6x$ is option 3. $x= \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .$

Step-by-step explanation:

Step 1:

First, we must bring the equation to the form of $ax^{2} +bx +c =0.$

So $-5 +2x^{2} = -6x$ becomes $2x^{2} +6x-5=0.$

The value of a is the coefficient of the $x^{2}$ term, the value of b is the coefficient of x term and c is the coefficient of the constant term.

Comparing the above equation to $ax^{2} +bx +c =0,$ we get $a = 2, b = 6,$ and $c=-5.$

We have the formula $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}.$

Step 2:

By substituting the known values, we get

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} =\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)}.$

$\frac{-6 \pm \sqrt{6^{2}-4 (2)(-5)}}{2 (2)} = \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .$

This is the third option.

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