Answer:
k=2
Problem:
if the equation x^2 +(k+2)x+2k=0 has equal roots,then the value of k is ..
Step-by-step explanation:
Since the coefficient of x^2 is 1, we can use this identity to aid us: x^2+bx+(b/2)^2=(x+b/2)^2.
So we want the following:
[(k+2)/2]^2=2k
Apply the power on the left:
(k+2)^2/4=2k
Multiply both sides by 4:
(k+2)^2=8k
Expand left side:
k^2+4k+4=8k *I used identity (x+c)^2=x^2+2xc+c^2
Subtract 8k on both sides:
k^2-4k+4=0
Factor using the identity mentioned a couple lines above:
(k-2)^2=0
Since zero squared is zero, we want k-2=0.
Adding both sides by 2 gives k=2.
The correct answer is 48%
There are 10 even numbers from 1 to 21.
That makes the probability of an even number 10 out 21.
10 / 21 x 100 = 48%
Answer:
3
Step-by-step explanation:
AB = 1 unit
A'B' = 3 units
The scale of dilation = A'B'/AB
Therefore:
scale of dilation = 3 units / 1 unit = 3
This means that ABC was dilated or enlarged in size by multiplying every of its segment by 3. In essence, A'B'C' is 3 times the size of ABC.
The integer that represents this -45.