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3 years ago

Lines AB and CD are parallel. If 6 measures (3x - 34)°, and 8 measures 145°, what is the value of x?

Mathematics

1 answer:

Trava [24]3 years ago

3 0

Answer:

x=23

Step-by-step explanation:

180-145= 35 so you have to set the equation to 35. 3x-34=35. add 34 to each side. now you have 3x=69. divide 3 on each side and you get x=23

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3 years ago

Estimate the amount of tip to include if you want to leave a 20% tip on a Lyft ride of<br> $8.

tankabanditka [31]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Use y = mx + b to determine the equation of a line with a slope -5, passing through the point (-2,4).

Maksim231197 [3]

Answer:

$y=-5x-6$

Step-by-step explanation:

Hi there!

In $y=mx+b$ , m is the slope of the line and b is the y-intercept (the value of y when x is 0). y and x remain the same but m and b are replaced with numbers.

Given that the slope is -5, plug it into $y=mx+b$ :

$y=-5x+b$

Now, to solve for b, plug in the given point (-2,4):

$4=-5(-2)+b\\4=10+b$

Subtract 10 from both sides to isolate b:

$4-10=10+b-10\\-6=b$

Therefore, the y-intercept of this line is -6. Plug this back into $y=-5x+b$ as b:

$y=-5x-6$

I hope this helps!

4 0

3 years ago

Use an appropriate Taylor series to find the first four nonzero terms of an infinite series that is equal to sin(5/2).

koban [17]

Answer:

2.5, -2.61, 0.81, -0.12

Step-by-step explanation:

The taylor series of the function sin(x) around zero is given by

$sin(x)=\sum_{n=0}^{\infty}\dfrac{(-1)^k}{(2k-1)!}x^{2k+1}=x-\dfrac{x^3}{3!}+\dfrac{x^5}{5!}-\dfrac{x^7}{7!}$

Therefore,

$\sin(\frac{5}{2})=\dfrac{5}{2}-\dfrac{[\frac{5}{2}]^3}{3!}+\dfrac{[\frac{5}{2}]^5}{5!}-\dfrac{[\frac{5}{2}]^7}{7!}+...$

hence the first four nonzero terms of the series are

$\dfrac{5}{2}=2.5\\\\-\dfrac{[\frac{5}{2}]^3}{3!} \approx -2.61\\\\\dfrac{[\frac{5}{2}]^5}{5!} \approx 0.81\\\\-\dfrac{[\frac{5}{2}]^7}{7!} \approx -0.12$

6 0

3 years ago