Answer:
2nd car is running faster than the first car by 2.01 units.
Step-by-step explanation:
Let's assume that
- the velocity of first car,

- and the velocity of second car

=> speed of first car,



= 32.01 units
and speed of second car,

= 30 units

= 2.01 units
Hence, 2nd car is running faster than the first car by 2.01 units.
Y=2x
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Answer:
Option A.) 88 inches
Step-by-step explanation:
step 1
Find the circumference of the wheel
we know that
The circumference of a circle is equal to

we have


substitute

Answer:u will kno3
Step-by-step explanation:6 in the side the top 2 the top
X^2 = 9x + 6
x^2 - 9x - 6 = 0
use quadratic formula : (-b (+-) sqrt b^2 - 4ac) / (2a)
a = 1, b = -9, c = -6
now we sub
x = (-(-9) (+-) sqrt -9^2 - 4(1)(-6)) / 2(1)
x = 9 (+-) sqrt 81 + 24)/2
x = 9 (+-) sqrt 105) / 2
x = 9/2 + 1/2 sqrt 105 or x = 9/2 - 1/2 sqrt 105