Question

How wide is a poster that has a length of

Answer 1

D
5/2
becuase 9/2 times 5/2 is 45/4 so that is the answer

Answer 2

Answer:

The correct option is D.

Step-by-step explanation:

Given information:

Length of the poster = $\frac{9}{2}$ ft

Area of the poster = $\frac{45}{4}$ ft²

We need to find the width of the poster.

The area of a rectangular poster is

$A=l\times w$

where, l is length and w is width.

Substitute $A=\frac{45}{4}$ and  $l=\frac{9}{2}$ in the above formula.

$\frac{45}{4}=\frac{9}{2} \times w$

$\frac{45}{4}=\frac{9w}{2}$

On cross multiplication we get

$45\times 2=9w\times 4$

$90=36w$

Divide both sides by 36.

$\frac{90}{36}=w$

Cancel out common factors.

$\frac{5}{2}=w$

The width of the poster is 5/2 ft.

Therefore the correct option is D.