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3 years ago

How wide is a poster that has a length of

Mathematics

2 answers:

stellarik [79]3 years ago

8 0

D
5/2
becuase 9/2 times 5/2 is 45/4 so that is the answer

polet [3.4K]3 years ago

6 0

Answer:

The correct option is D.

Step-by-step explanation:

Given information:

Length of the poster = $\frac{9}{2}$ ft

Area of the poster = $\frac{45}{4}$ ft²

We need to find the width of the poster.

The area of a rectangular poster is

$A=l\times w$

where, l is length and w is width.

Substitute $A=\frac{45}{4}$ and $l=\frac{9}{2}$ in the above formula.

$\frac{45}{4}=\frac{9}{2} \times w$

$\frac{45}{4}=\frac{9w}{2}$

On cross multiplication we get

$45\times 2=9w\times 4$

$90=36w$

Divide both sides by 36.

$\frac{90}{36}=w$

Cancel out common factors.

$\frac{5}{2}=w$

The width of the poster is 5/2 ft.

Therefore the correct option is D.

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Which proportion can be used to show that the slope of JL is equal to the slope of MP

Ilya [14]

Answer:

See below and attached

Step-by-step explanation:

As per the graph we have:

Coordinates of JL are J(-7, 4), L(-4, 0)

Coordinates of MP are M(-10, 8), P(-1, -4)

Slope formula is:

m = (y₂ - y₁)/(x₂ - x₁)

Slope of JL:

(0 - 4)/(-4-(-7)) = - 4 / 3

Slope of MP:

(-4 -8)/(-1- (-10)) = -12 / 9 = - 4/3

5 0

3 years ago

Which long division problem can be used to prove the formula for factoring the difference of two perfect cubes?

Lostsunrise [7]

Answer:

The correct options, rearranged, are:

Options:

$A)(a^2+ab+b^2)/(a-b)\\\\B)(a^2-ab+b^2)/(a+b)\\\\C)(a^3+0a^2+0ab^2-b^3)/(a+b))\\\\ D)(a^3+0a^2+0ab^2-b^3)/(a-b)$

And the asnwer is the last option (D).

Explanation:

You need to find which long division can be used to prove the formula for factoring the difference of two perfect cubes.

The difference of two perfect cubes may be represented by:

$a^3-b^3$

And it is, as a very well known special case:

$a^3-b^3=(a-b)(a^2+ab+b^2)$

Then, to prove, it you must divide the left side, $a^3-b^3$ , by the first factor of the right side, $a-b$

Note that, to preserve the places of each term, you can write:

$(a^3-b^3)=(a^3+0a^2+0ab^2-b^3)$

Then, you have:

$(a^3+0a^2+0ab^2-b^3)=(a-b)(a^2+ab+b^2)$

By the division property of equality, you can divide both sides by the same factor, which in this case will be the binomial, and you get:

$(a^3+0a^2+0ab^2-b^3)/(a-b)=(a^2+ab+b^2)$

That is the last option (D).

3 0

3 years ago

Read 2 more answers

Juile planted a rectangular garden that is 20 feet long. She placed 56 feet of fencing around her garden. Draw and label a sketc

Xelga [282]

Answer:

Step-by-step explanation:

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

She placed 56 feet of fencing around her garden. This means that the perimeter of the garden is 56 feet. If the length of the rectangular garden is 20 feet, i means that

2(20 + W) = 56

Dividing through by 2, it becomes

20 + W = 28

W = 28 - 20

W = 8 feet

The formula for determining the area of a rectangle is expressed as

Area = length × width

Therefore,

Area = 8 × 20 = 160 square feet

6 0

4 years ago

Geometry help needed Use O for exercises 6-8 6. what is the perimeter of triangle abc

iris [78.8K]

Perimeter of triangle ABC is 20 units.

Solution:

The image for reference is attached below.

Given AE = 2, BD = 5 and CF = 3

Two tangents drawn from an external point to a circle are equal in length.

AD = AE, BF = BD and CE = CF

Therefore, AD = 2, BF = 5 and CE = 3

Perimeter of the triangle = sum of the three sides

Perimeter of triangle ABC = AB + BC + CA

= AD + BD + BF + CF + CE + AE

= 2 + 5 + 5 + 3 + 3 + 2

= 20

Hence, perimeter of triangle ABC is 20 units.

6 0

4 years ago

What’s 4x + 7y + 4 + 5x + y

fomenos

Hello!

Okay, so first we need to add like terms... so first, add the terms with the same variables. That gives us:

9x + 7y + 4 + y

Now add 7y and y

That gives us:

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3 years ago

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