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BlackZzzverrR [31]
3 years ago
12

How does an animal cell react when there is no glucose available to carry out cellular respiration?

Biology
2 answers:
Verdich [7]3 years ago
6 0

Answer:

B) It breaks down polysaccharides such as starch.

Explanation:

Polysaccharides are long chains of monosaccharides like glucose joined together with glycosidic linkages. While plants can simply make glucose via photosynthesis, animals rely on glucose sourced from their diet. In animals, glucose is stored as glycogen; however, plant storage polysaccharides like starch are regularly broken down through digestion using enzymes.

Enzymes are proteins which catalyze chemical reactions like the breakdown of large polysaccharides. Alpha amylase, an enzyme produced in the pancreas, is also found in human saliva; it catalyzes the hydrolysis, or breakdown of starch into glucose. Amylase acts on polysaccharides bonds at random points along the chain by splitting the α 1-4 glycosidic bonds. This produces maltose, dextrin and glucose; this glucose is used in ATP synthesis via <em>respiration, ethyl alcohol fermentation and lactic fermentation</em>.

Semmy [17]3 years ago
5 0

Answer:

Option B ,

Explanation:

When there is no sufficient glucose available for cellular respiration, the cell in animals starts decomposing molecules also known as polysaccharide that could satisfy their glucose requirement. Some of the common polysaccharide in animals are - Amylose and amylopectin (plant starch found in animals), glycogen, cellulose, lipids and proteins etc. These poly saccharides are  complex compounds containing glucose matrix which are broken down with the assistance of an enzyme to release glucose.

Hence, option B is correct

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Answer:

c  a b

Explanation:

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3 years ago
A population of aliens with similar genetics as humans is affected by a homozygous recessive condition known as "xbziq." This co
likoan [24]

Answer:

24%

Explanation:

The given genetic trait is homozygous recessive and the frequency of homozygous recessive genotypes in the population is 2%.

Therefore, frequency of homozygous recessive genotypes (q2) = 2% = 0.02

Frequency of homozygous recessive allele (q) = square root of 0.02 = 0.141

Since p+q =1 (here, p = frequency of dominant allele).

So, p= 1-q = 1-0.141 = 0.859

The frequency of heterozygous carrier genotypes in the population = 2pq = 2 x 0.141 x 0.859 = 0.24 or 24%

5 0
3 years ago
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egoroff_w [7]

Answer:

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Explanation:

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3 0
3 years ago
What is alternation of generation and describe how it changes through plant evolution?
Zina [86]
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4 0
4 years ago
A plant is grown in a pot, and is placed next to a window. Sunlight
miskamm [114]

Answer:it will grow to the left

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