Answer:
wait is there suppose to be a link ? nevermind the 2nd one,4th one, & 1st one
Step-by-step explanation:
Answer: x2+10x-75= (x-5)(x+15)
Step-by-step explanation:
Ok so we factor by thinking of numbers that can add to 10 and multiple to get -75. so those 2 numbers were -5 and 15. Hope this helps xD
Y = 9x + 47
and
xy = 18601860
substitute for y in second equation:-
x(9x + 47) = 18601860
9x^2 + 47x - 18601860 = 0
factoring 18601860 is a pain so we use the quadratic formula:-
x = [(-47 +/- sqrt (47^2 - 4*9*-18601860)] / 18
this gives x = 1435 , -1440 so we want x=1435 as its positive
this make y = 9(1435) + 47 = 12962
the 2 integers are 1435 and 12962
Answer:5 and 3
So we let the number take the letter b, anc the expression of the question is:
b^2+15=8×b.....so
b^2+15=8b
Then we take the 8b to the other side of the equal sign so that it becomes...
b^2+15-8b=0
Hence it becomes a quadatic equation following the principle ax^2+bx+c where x is the unknown...
From there we work out to get two different numbers...either b-5=0
b=5
Or b-3=0
b=3
So the two numbers are 5 and 3