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alexandr402 [8]
3 years ago
12

Evaluate √7x(√x−7√7) please Show your Work thanks.

Mathematics
2 answers:
Veronika [31]3 years ago
8 0

 expand by multiplying <span><span>√<span>7x</span></span>⋅<span>√x</span></span> and <span><span>√<span>7x</span></span>⋅7<span>√7</span></span> 

<span><span>√<span>7x</span></span><span>(<span>√x</span>−7<span>√7</span>)</span>=<span>√<span>7x</span></span>⋅<span>√x</span>−<span>√<span>7x</span></span>⋅7<span>√7</span></span>

<span>You can make√<span>7x</span></span> into <span><span>√7</span>⋅<span>√x</span></span>

<span><span>=<span>√7</span>⋅<span><span>√x</span>⋅<span>√x</span></span>−<span>√7</span>⋅<span>√x</span>⋅7⋅<span>√7</span></span><span>=<span>√7</span>⋅<span><span>(<span>√x</span>)</span>2</span>−<span><span>(<span>√7</span>)</span>2</span>⋅<span>√x</span>⋅7</span></span>

since squaring and square roots are opposite, they cancel

<span><span>=<span>√7</span>⋅x−7⋅<span>√x</span>⋅7</span>=x√7−49√x
I hope the square root symbols worked. I had to copy and paste from word. Hopefully this is what you needed!
</span>
Greeley [361]3 years ago
5 0
Remember
(\sqrt{a})(\sqrt{b})=\sqrt{ab}


first distribute

\sqrt{7x^2}-7\sqrt{49x}=
(\sqrt{x^2})(\sqrt{7})-7(\sqrt{49})(\sqrt{x})=
x\sqrt{7}-7(7)\sqrt{x}=
x\sqrt{7}-49\sqrt{x} is simlified form
to evaluate, we would need a value for x

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