2 toy cars cost 3 dollars

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

6 0

Answer:

$27

Step-by-step explanation:

The relationship between the number of toy cars and the cost of cars expressed in the given data. The following is the pattern that can be formed from the given data. It is as follows :

2 × 1 + 1 = 3

4 × 1 + 2 = 6

6 × 1 + 3 = 9

8 × 1 + 4 = 12

10 × 1 + 5 = 15

12 × 1 + 6 = 18

14 × 1 + 7 = 21

16 × 1 + 8 = 24

18 × 1 + 9 = 27

So, the cost of 18 toy cars is 27 dollars. Hence, this is the required solution.

vichka [17]3 years ago

4 0

It is $3 for every two cars. 18 cars is equal to 9 bundles of 2, 3 times 9 =27. So the answer is $27

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What is x if n≠m? Please help!

lorasvet [3.4K]

Answer: $x = \frac{mn(q - p)}{n-m}\\\\$

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Work Shown:

Part 1

$\frac{x-m}{m} + p = \frac{x-n}{n} + q\\\\\frac{x-m}{m} - \frac{x-n}{n} = q - p\\\\\frac{n(x-m)}{mn} - \frac{m(x-n)}{mn} = q - p\\\\\frac{xn-mn}{mn} - \frac{xm-mn}{mn} = q - p\\\\\frac{xn-mn-(xm-mn)}{mn} = q - p\\\\$

Part 2

$\frac{xn-mn-xm+mn}{mn} = q - p\\\\\frac{xn-xm}{mn} = q - p\\\\\frac{x(n-m)}{mn} = q - p\\\\x(n-m) = mn(q - p)\\\\x = \frac{mn(q - p)}{n-m} \\\\$

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Explanations:

There are quite a bit of steps. I decided to break things into two parts.
The goal is to get x all by itself on its own side, which is why I subtracted (x-n)/n from both sides in part 1, step 2. I also subtracted p from both sides.
Afterward, I gave each fraction the LCD mn. I multiplied top and bottom of the first fraction by n/n. I did a similar operation to the second fraction, but with m instead.
From there, we distribute and simplify. The mn terms cancel on the left side numerator (second step of part 2).
The n≠m is there to prevent the denominator (n-m) from being zero. We cannot divide by zero.
If the formulas don't properly display, then you might have to refresh the page.

7 0

2 years ago

Im studying for my ged can you help with this ?

jarptica [38.1K]

What do you need help with on it?

6 0

3 years ago

You can also write fractions as percents. To write a fraction as a percent, find an ________________________ ___________________

TiliK225 [7]

Answer:

common numerator and denomanator

Step-by-step explanation: