Answer:
The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).
It would be A. <span>y = −2x − 4.
Hope this helps!!
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Hi there! :)
<u>Answer:</u>
The car needs <u>6 gallons</u> of gas to travel 192 miles.
Step-by-step explanation:
In order to answer your question, you'll need to use the cross product method:
32 miles → 1 gallon
192 miles → X gallons
<u>(1 × 192)</u> ÷ 32 = X gallons
<u>192 ÷ 32</u> = X gallons
<u>6</u> = X gallons
There you go! I really hope this helped, if there's anything just let me know! :)
700 what and how much did they cost? the problem wasnt typed out right