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2 years ago

MATHEMATICS: can anybody help or show me how to do this. look at the picture i need help with question 3?

Mathematics

1 answer:

Alekssandra [29.7K]2 years ago

5 0

It wants you to come up with three events. You'll place them on the line right above, where you think they would go.

For example, if your first event was "seeing a unicorn" you would plot it by "impossible." Some things have a fifty fifty chance, or are likely, like you finding a penny. Use any scenario you can think of. How likely is it that it would come true?

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Whats 10000 + 1 plus 2

MrMuchimi

1,000 + 1 =1,001 + 2 = 1,002
I hope this helps

7 0

3 years ago

Read 2 more answers

The sum of three consecutive rven integers is 72. Let x represent the first integer, x+2 represent the srcond integer, and x+ 4

Vsevolod [243]

Given parameters:

First term of the sequence = x

Second term = x + 2

Third term = x + 4

Sum of the first three terms = 72

Unknown:

First term of the sequence = ?

Solution:

The sum of the first three terms is unknown;

(x) + (x + 2) + (x + 4) = 72

Solve for x;

x + x + 2 + x + 4 = 72

3x + 6 = 72

3x = 72 - 6

3x = 66

x = $\frac{66}{3}$ = 22

The first term of the sequence is 22

5 0

2 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

Solve the system of inequalities and indicate all the integers which are in the solution set:

elena-s [515]

1.) a>10
2.) a<3.5
How I got it: 1.) Subtract 3 from both sides, leaving -2a<10.
2.) Divide by -2 from both sides, remember to flip the inequality sign when dealing with negatives. This leaves you with a>10.
For number 2.) I divided both sides by 5, leaving a<3.5, though this answer may be wrong.

8 0

3 years ago

Perform the indicated operation and simplify the result.

Finger [1]

Answer:

7/ (3a-1)

Step-by-step explanation:

3a^2 -13a +4 28+7a

------------------ * --------------------

9a^2 -6a+1 a^2 -16

Factor

(3a-1)(a-4) 7(4+a)

------------------ * --------------------

(3a-1) (3a-1) (a-4)(a+4)

Cancel like terms

1 7

------------------ * --------------------

(3a-1) 1

Leaving

7/ (3a-1)

3 0

3 years ago