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Allushta [10]
3 years ago
10

David, Ben, and Jordan shared stickers in a ratio of 8 : 9 : 10. If Ben had 36 stickers, how many stickers did Jordan have?

Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

Jordan had 40 stickers.

Step-by-step explanation:

For this ratio, we have David:Ben:Jordan as 8:9:10, and so we need to make it as a more complex fraction, 8/9/10, now we need a multiplier to get us from 9 stickers of Jordan to 36, like a giant one. The common multiplier in this case is 4, and we know that the values must always stay proportional. We multiply everything by 4,and we get a final ratio of 32:36:40, and since Jordan is the last in the ratio David:Ben:Jordan, Jordan ends up with 40 stickers.

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GIVEN THAT TITAN HAS A RADIUS OF 2575 KM WHICH IS COVERED BY 600 KM ATMOSPHERE. WHAT
Ber [7]

Answer:

  87.4%

Step-by-step explanation:

The radius to the top of the atmosphere as a fraction of the moon's radius is ...

  (2575 +600)/2575 ≈ 1.23301

The ratio of the moon's volume with atmosphere to the moon's volume without is the cube of this, or 1.87456

Then the ratio of the atmosphere's volume to the moon's volume is ...

  (1.87456 -1)/1 = 0.87456

Atmospheric haze is about 87.4% of the moon's volume.

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We have assumed that the desired ratio is to the solid moon's volume, not the volume of moon and atmosphere together. The latter ratio would be 0.875 to 1.875 or about 46.7%.

3 0
3 years ago
HELP ME TO ANSWER THIS PLEASE JUST KINDA CONFUSED.
yulyashka [42]

Answer:

A = 5

B = 9

Step-by-step explanation:

This was very simple!

Nancy needs at least 15 boxes of travoprost but she only has 10. To find out how many she needs, we subtract 15 from 10 to get 5 boxes

Nancy also needs at least 12 boxes of latanoprost but she only has 3. To find out how many she needs, we subtract 12 from 3 to get 9 boxes

Therefore A = 5 boxes; B = 9 boxes

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3 0
3 years ago
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Please help me <br><br><br>i'll mark u as brainly if u give me the correct answers
jarptica [38.1K]

Answer:

49π cm²

Step-by-step explanation:

Diameter (d) = 14 cm

Radius (r) = d/2 = 14/2 = 7 cm

Area of a circle

= πr²

= π × (7)²

= 49π cm²

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8 0
2 years ago
Read 2 more answers
What is the solution set of the equation 6x^2 - 18x - 18 =6?
dybincka [34]

Answer:

The solution set is {4, -1}

Step-by-step explanation:

6x²- 18x -18 = 6

6x²- 18x -18 - 6 = 0

6x²- 18x -24 = 0

6(x² - 3x - 4) = 0

6(x - 4)(x + 1) = 0

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x - 4 = 0 ;   x + 1 = 0

x = 4           x = - 1

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3 0
2 years ago
Construct a quadrilateral MINT such that MI= 5cm, IN = 6cm, NT = 7cm, TM=3cm and MN =9cm
Tems11 [23]

From the given dimensions, of MI, IN, NT, TM, and MN, the quadrilateral

MINT can be drawn as shown in the attached image.

<h3>What are the steps for the construction of MINT?</h3>

The given dimensions of the quadrilateral MINT are;

MI = 5 cm

IN = 6 cm

NT = 7 cm

TM = 3 cm

MN = 9 cm

The side MN is a diagonal of MINT, therefore;

ΔMIN, and ΔMTN are triangles with a common base = MN

The steps to construct MINT are therefore;

  • Step 1; Draw the line MN = 9 cm.

  • Step 2; Place the compass at point <em>M</em> and with a radius MI = 5 cm, draw an arc on one side of MN.

  • Step 3; Place the compass at <em>N</em> and with radius IN = 6 cm, draw an arc to intersect the arc dawn in step 1 above.

  • Step 4; Place an arc at point <em>M</em> and with radius TM = 3 cm draw an arc on the other side of MN.

  • Step 5; Place the compass at point <em>N</em> and with radius NT = 7 cm, draw an arc to intersect the arc drawn in step 3.

  • Step 6; Join the point of intersection of the arcs to points <em>M</em> and <em>N</em> to complete the quadrilateral MINT.

Please find attached the drawing (showing the construction arcs) of the

quadrilateral MINT created with MS Word.

Learn more about types of geometric construction here:

brainly.com/question/785568

brainly.com/question/8607612

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