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Lesechka [4]
3 years ago
8

Solve 2x^2 + 26 = 0 to identify the roots

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
4 0
2x^2=-26
x^2=-13
x=(+/-)sqrt(13)i
Serggg [28]3 years ago
4 0

Answer:

2nd and 3rd part of the problem:

The roots are imaginary because of the NEGATIVE RADICAND

There are two roots because of the NEED TO IDENTIFY + AND- ROOTS OF THE RADICAND


Step-by-step explanation:


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For the given function h(x), we have:

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First, we want to get the values of x at which we have maximums. To do that, we need to see the value in the horizontal axis at where we have maximums.

By looking at the horizontal axis, we can see that the maximums are at:

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If you want to learn more about maximums:

brainly.com/question/1938915

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3 years ago
Over the last three evenings Lucy received a total of 122 phone calls at the call center. The first evening she received 10 fewe
Zanzabum

Answer:

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Please explain how they plugged the removable discontinuity in this question.
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In the given example, f(x) is factorized to reveal a common factor of x-1 in the numerator and denominator. We have x\neq1 if x\to1, so x-1\neq0 so we can simplify

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8 0
1 year ago
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10. 8x+4y=4. y=mx+b
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