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3 years ago

Solve 2x^2 + 26 = 0 to identify the roots

Mathematics

2 answers:

jok3333 [9.3K]3 years ago

4 0

2x^2=-26
x^2=-13
x=(+/-)sqrt(13)i

Serggg [28]3 years ago

4 0

Answer:

2nd and 3rd part of the problem:

The roots are imaginary because of the NEGATIVE RADICAND

There are two roots because of the NEED TO IDENTIFY + AND- ROOTS OF THE RADICAND

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Frankie solved the math problem below. Find the error in Frankie's work and explain it in words, using math language. 2 1/3 - 1

HACTEHA [7]

Given:

The expression is

$2\dfrac{1}{3}-1\dfrac{2}{5}$

To find:

The error in Frankie's work.

Solution:

We need to simplify $2\dfrac{1}{3}-1\dfrac{2}{5}$ , so

$2\dfrac{1}{3}=2\dfrac{1}{3}\times \dfrac{5}{5}$

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and,

$1\dfrac{2}{5}=-1\dfrac{2}{5}\times \dfrac{3}{3}$

$1\dfrac{2}{5}=-1\dfrac{6}{15}$

Now,

$2\dfrac{1}{3}-1\dfrac{2}{5}=2\dfrac{5}{15}-1\dfrac{6}{15}$

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$2\dfrac{1}{3}-1\dfrac{2}{5}=2+\dfrac{5}{15}-1-\dfrac{6}{15}$

$2\dfrac{1}{3}-1\dfrac{2}{5}=1-\dfrac{1}{15}$

$2\dfrac{1}{3}-1\dfrac{2}{5}=\dfrac{14}{15}$

Therefore, there is error in Frankie's last step. In that step, he did not subtract the mixed fraction correctly.

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3 years ago