3 years ago

Solve 2x^2 + 26 = 0 to identify the roots

2 answers:

4 0

2x^2=-26
x^2=-13
x=(+/-)sqrt(13)i

4 0

Answer:

2nd and 3rd part of the problem:

The roots are imaginary because of the NEGATIVE RADICAND

There are two roots because of the NEED TO IDENTIFY + AND- ROOTS OF THE RADICAND

Step-by-step explanation:

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