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Rudik [331]
3 years ago
9

Simplify (3n – 2m)2 = ?

Mathematics
1 answer:
Neko [114]3 years ago
5 0
Is the 2 at the end indicating squared?

If so,

(3n-2m) (3n-2m) = ?

9n-6nm-6nm+4m = ?

9n+4m-12nm = ?

hope this helps!
You might be interested in
Find the area when the circumference is 50.24 cm
nevsk [136]

Answer:

201

Step-by-step explanation:

C = 2pi.R

50.24/2pi = R

R= 8

area = pi R² = pi x 8² = 201

7 0
2 years ago
If g(x) = 3x - 4, what is the value of g-(g(-2))?<br> 100<br> X + 4<br> 3<br> 10
kozerog [31]

-g(-2) is 10    

<u>Step-by-step explanation:</u>

Step 1:

Given g(x) = 3x - 4. Find g(-2).

⇒ g(-2) = 3 × -2 - 4 = -6 - 4 = -10

Step 2:

Find -g(-2)

⇒ -g(-2) = -(-10) = 10

3 0
3 years ago
If a pair of regular dice are tossed once, use the expectation formula to determine the expected sum of the numbers on the upwar
Darya [45]

Answer:

The expected sum of the numbers on the upward faces of the two dice is 7.

Step-by-step explanation:

Consider the provided information.

If two pair of dice tossed the possible out comes are:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),  (5,6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5),  (6,6)

Now we need to find the expected sum of the numbers on the upward faces of the two dice.

The expected sums can be:

Sum:    2,      3,       4,       5,      6,      7,       8,        9,      10,    11,      12

Prob: 1/36, 2/36, 3/36, 4/36, 5/36, 6/36, 5/36, 4/36, 3/36, 2/36, 1/36

As we know that the expectation of experiment can be calculated as:

P(S_1)\cdot S_1+P(S_2)\cdot S_2+........+P(S_n)\cdot S_n

Here S represents the numerical outcomes and P(S) is the respective probability.

Substitute the respective values in the above formula.

=2\times\frac{1}{36}+3\times\frac{2}{36}+4\times\frac{3}{36}+5\times\frac{4}{36}+6\times\frac{5}{36}+7\times\frac{6}{36}+8\times\frac{5}{36}+9\times\frac{4}{36}+10\times\frac{3}{36}+11\times\frac{2}{36}+12\times\frac{1}{36}\\=\frac{252}{36}\\=7

Hence, the expected sum of the numbers on the upward faces of the two dice is 7.

8 0
4 years ago
I'm not very good at math
emmasim [6.3K]
Okay so, I am assuming the model is smaller so it would be 0.34m long.

The model has to be 200 times smaller than the actual plane
Divide 68/200 and you get 0.34
Then to check your answer, multiply 0.34 by 200 which is 68 meaning
0.34:68 is equal to 1:200

Assuming the model is bigger (just in case) it would be 13,600m long.

The in this scenario, the model has to be 200 times bigger so it would be 68(200) which is 13,600

Hope this helps
6 0
3 years ago
2(4+2x) &gt; 5x+5<br> Solve the inequality
seropon [69]

Answer:

x < 3

Step-by-step explanation:

Apply distributive property on the left of the inequality to get rid of the parenthesis:

8+4x > 5x+5

subtract 4x from both sides to group all terms with x on the right:

8 > 5x-4x+5

8 > x +5

Now subtract 5 from both sides to collect all numerical terms on the left:

8 - 5 > x

3 > x

Therefore the solution to the inequality are of those real numbers strictly smaller than 3.

The inequality can be written as x < 3 or also as we had it initially: 3 > x

Notice that the opening of the angle symbol is always facing the number 3 , meaning that 3 is the larger of the two numerical objects that are compared.

6 0
3 years ago
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