We would have the following sample space:
(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)
Those give us these sums:
2, 3, 4, 5
3, 4, 5, 6
4, 5, 6, 7
5, 6, 7, 8
P(sum of 2) = 1/16 =0.0625
P(sum of 3) = 2/16 = 0.125
P(sum of 4) = 3/16 = 0.1875
P(sum of 5) = 4/16 = 0.25
P(sum of 6) = 3/16 = 0.1875
P(sum of 7) = 2/16 = 0.125
P(sum of 8) = 1/16 = 0.0625
The experimental probability of each event is as follows:
- Landing open side up = 1/50 = 0.02 = 2%.
- Landing closed side up = 5/50 = 1/10 = 0.1 = 10%.
- Landing on its side = 44/50 = 0.88 = 88%.
The experimental probability of an event is the ratio of the number of outcomes that favored the event to the total number of outcomes in the experiment.
In the question, we are given that Jake tossed a paper cup 50 times and recorded the position how it landed, which is shown in the table:
Open-sided up: 1
Closed side up 5
On the side: 44.
We are asked to determine the experimental probability of each outcome.
The number of outcomes, when the landing is open-sided up is 1.
The number of outcomes, when the landing is closed-sided up is 5.
The number of outcomes, when the landing is on the side up is 44.
The total number of times the experiment took place is 50.
Thus, the experimental probability of each event is as follows:
- Landing open side up = 1/50 = 0.02 = 2%.
- Landing closed side up = 5/50 = 1/10 = 0.1 = 10%.
- Landing on its side = 44/50 = 0.88 = 88%.
Learn more about the experimental probability at
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Me being a junior in high school and not knowing middle school math
B = 3h . . . . . . . .given by the problem statement
A = (1/2)bh . . . . formula for the area of a triangle
486 cm² = (1/2)*(3h)*h . . . substitute given information
(2/3)*486 cm² = h² . . . . . .multiply by 2/3
√324 cm = h . . . . . . . . . . . . . .take the square root
The height is 18 cm.
The base is 3*18 = 54 cm.
1
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2
Put it like that and there’s your constant
