Answer:
The first, the second and the forth ones, Hope i can help out
Step-by-step explanation:
Answer:288
Step-by-step explanation:
If y varies directly as x^2
i.e y varies directly as x * x
and y =72, when x =3
therefore, 72 = k* 3*3 9 (where k is constant)
72=k9
k = 72/9
=8
The value of y, when x =6 will be
y = 8 * 6^2
8*36 = 288
Answer:
<em><u>1</u></em><em><u>.</u></em><em><u>d</u></em>
<h3>2. c</h3>
3.A
4.E
<h2>5.B yan po answer ko </h2>
Answer:
Step-by-step explanation:
We will use the standard formula for half-life:
Where A₀ is the initial amount, a is the half-life, d is the time for one half-life, and t is the number of days.
So, we will substitute 1/2 for a and 24.3 for d. This yields:
We have a 3 gram sample. Therefore, our initial amount A₀ is 3:
And we want to find the remaining sample after 10 days. So, t=10. Substitute:
Use a calculator. So:
Therefore, for a 3 gram sample of Phosphorous-32 with a half-life of 24.3 days, after 10 days, there will be approximately 2.255 grams remaining.
Answer:
1r
Step-by-step explanation:
Sorry i am tired of explaining how it goes