All categories

3 years ago

I would really appreciate help on these. Will mark Brainliest and worth 15 points. <3

Mathematics

1 answer:

cestrela7 [59]3 years ago

3 0

The Answer to number 1 is 4

and the answer to number two should be 8

Hope this helps

You might be interested in

Please help me fast!!!

Natasha2012 [34]

Y>3 is the correct answer because more than 3 inches of rain fell.

4 0

3 years ago

Read 2 more answers

a football gains 8 yards on their first play. they lose 12 yards on the next play.. which integers represent the two plays?

9966 [12]

8 yards - 12 yards = - 4

The integer is -4

5 0

3 years ago

Read 2 more answers

Please someone help?!!<br><br> WILL MARK BRAINLIEST^^^^

garik1379 [7]

The answer for that question is about 3 I think is this mathswatch

8 0

3 years ago

Read 2 more answers

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

3 years ago

Find the area of the shaded polygons<br> PLS HELP ASAP!!

matrenka [14]

Answer:

4.5

Step-by-step explanation:

I do RSM

5 0

3 years ago