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Kruka [31]
3 years ago
13

What is

tle=" \frac{4}{8} - \frac{1}{4} " alt=" \frac{4}{8} - \frac{1}{4} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
marysya [2.9K]3 years ago
5 0
Hello there, and thank you for posting your question here on brainly.

Something I noticed right away is that 4/8 can be simplified.

4/8 ===> 2/4

So now we have 2/4 - 1/4

Just subtract the numerators only.

2/4 - 1/4 = 1/4

1/4 cannot be simplified, so 1/4 is your final answer.

Hope this helped!! ☺♥
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<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

If a = 6 - \sqrt{35}, find the value of a² + \frac{1}{a²}

<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

a = 6 - \sqrt{35} (Given)

Now, first of all we have to find the value of \frac{1}{a}.

So, \frac{1}{a} = \frac{1}{6 \: - \: \sqrt{35}}

\frac{1}{a} = \frac{6 \: + \sqrt{35}}{(6 \: - \: \sqrt{35})(6 \: + \: \sqrt{35})}

\frac{1}{a} = \frac{6 \: + \sqrt{35}}{(6)² \: - \: (\sqrt{35})²}

\frac{1}{a} = \frac{6 \: + \sqrt{35}}{36 \: - \: 35} (\because \sqrt{35} \: × \: \sqrt{35} \: = \: 35)

\frac{1}{a} = \frac{6 \: + \: \sqrt{35}}{1}

\frac{1}{a} = 6 + \sqrt{35}

Now, we have to find the value of a² + \frac{1}{a²}

So, a² + \frac{1}{a²} = (a \: + \frac{1}{a})² - 2.a.\frac{1}{a}

a² + \frac{1}{a²} = (6 \: - \sqrt{35} \: + \: 6 \: + \sqrt{35})² - 2

a² + \frac{1}{a²} = (12)² - 2

a² + \frac{1}{a²} = 144 - 2

a² + \frac{1}{a²} = 142

The value of a² + \frac{1}{a²} is <u>1</u><u>4</u><u>2</u>. [Answer]

7 0
3 years ago
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