1*10^-6 is the answer, you look at how many prior figures there are, including the 0 before the decimal place, and that is your answer
Answer:
These two equations are related to each other by identity
Step-by-step explanation:
We have given equations
![\frac{x^2-1}{x+1}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2-1%7D%7Bx%2B1%7D)
We know the algebraic identity
![a^2-b^2=(a+b)(a-b)](https://tex.z-dn.net/?f=a%5E2-b%5E2%3D%28a%2Bb%29%28a-b%29)
So ![a^2-1^2=(x+1)(x-1)](https://tex.z-dn.net/?f=a%5E2-1%5E2%3D%28x%2B1%29%28x-1%29)
So ![\frac{x^2-1}{x+1}=\frac{(x+1)(x-1)}{x+1}=(x-1)](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2-1%7D%7Bx%2B1%7D%3D%5Cfrac%7B%28x%2B1%29%28x-1%29%7D%7Bx%2B1%7D%3D%28x-1%29)
So these two equations are related to each other by algebraic identity ![a^2-b^2=(a+b)(a-b)](https://tex.z-dn.net/?f=a%5E2-b%5E2%3D%28a%2Bb%29%28a-b%29)
Maybe The 30% And 70% Is In The Other Triangle And You Do The Same Thing Thats What I Am Guessing Not 100% Sure About It Because I Have Not Learned This Yet! :P
Answer:
C
Step-by-step explanation: