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SVEN [57.7K]
4 years ago
9

What are three problems the have the sum of 4

Mathematics
1 answer:
vladimir2022 [97]4 years ago
6 0
It will be all these
1+3
2+2
4+0
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Xander takes a quiz worth 150 points. Each question is worth 30 points. Sketch a graph to show his score if he misses 1,2,3,4 or
DaniilM [7]

Answer:

If he missed five questions he can get a zero

Step-by-step explanation:

7 0
3 years ago
David sent a survey to 12 classmates. One week laterb9 of the surveys were returned what percent of the surveys were returned
Olegator [25]
9 of 12 were returned which is the same as 9/12. Reduce the fraction...

9/12 = 3/4

To find percent we need the denominator to equal 100 so if we multiply by 25/25...

3/4 × 25/25 = 75/100 =

75%
4 0
3 years ago
I really need help with this
slega [8]
Check the picture below.

the radius, so-called because if we circumscribe the triangle in a circle, that'd be the radius of the circumcircle, is 3 inches, as you see there in the picture in red.

now, bear in mind that the triangle is an equilateral one, and therefore, 180/3 = 60, meaning all its interior angles are congruently 60°.

if we run the radius of the triangle, like there, it will cut one of those interior angles in half, namely the radius is an angle bisector, and if we run a perpendicular line to the bottom side, like the dashed one there, we end up with a 30-60-90 triangle, to which we can apply the 30-60-90 rule, as you see it there.

since we know what half of a side of the triangle is, as you see it there in blue, then we can use that and plug it in at

\bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}~~
\begin{cases}
s=length~of\\
\qquad a~side\\
-------\\
s=\stackrel{\frac{3\sqrt{3}}{2}+\frac{3\sqrt{3}}{2}}{3\sqrt{3}}
\end{cases}\implies A=\cfrac{(3\sqrt{3})^2\sqrt{3}}{4}
\\\\\\
A=\cfrac{(3^2\sqrt{3^2})\sqrt{3}}{4}\implies A=\cfrac{(9\cdot 3)\sqrt{3}}{4}\implies A=\cfrac{27\sqrt{3}}{4}

8 0
4 years ago
If you dunked a basketball and hung on to the rim, what force or forces would be acting on you while you were hanging on the rim
BabaBlast [244]
Selection A is appropriate.

_____
The rim is exerting an upward force on your fingers (creating tension in your fingers and arms); gravity is exerting a downward force on your body's center of mass.
5 0
4 years ago
Read 2 more answers
A survey is to be conducted in which a random sample of residents in a certain city will be asked whether they favor or oppose t
marshall27 [118]

Answer:

n=269 residents should be sample required to be sure that a 90% confidence interval for the proportion who favor the construction will have a margin of error no greater than 0.05

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p represent the real population proportion of interest

\aht p represent the estimated proportion for the sample

n is the sample size required (variable of interest)

z represent the critical value for the margin of error

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.10 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)

 We can assume that the estimates proportion is 0.5 since we don't have other info provided to assume a different value. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.64})^2}=268.96  

And rounded up we have that n=269

4 0
3 years ago
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