Answer:
Step-by-step explanation:
Alright, lets get started.
Please refer the diagram I have attached.
The width of the room is 30 meters.
If two beams will be making an angle, they will half the width.
There will be a right triangle made, so using SOH CAH TOA,
![cos x=\frac{adjacent}{hypotenuse}](https://tex.z-dn.net/?f=cos%20x%3D%5Cfrac%7Badjacent%7D%7Bhypotenuse%7D)
![cos x=\frac{15}{17}](https://tex.z-dn.net/?f=cos%20x%3D%5Cfrac%7B15%7D%7B17%7D)
taking cos inverse
x = ![cos^{-1} (\frac{15}{17} )](https://tex.z-dn.net/?f=cos%5E%7B-1%7D%20%28%5Cfrac%7B15%7D%7B17%7D%20%29)
x = 28.07° : Answer
Hope it will help :)
Answer:
In Fig. 8.27 , AP and, BP are tangents to a circle wit
Step-by-step explanation:
Answer:It is greater than 10 because as you add both distances from the image its greater than 10 by a bit, looking at the angle it gives you a bigger perspective in how far the cue ball is from the pocket
Its basically 8+6 which equals 14 but adding the way the angle is going the distance is shorter than 14 but greater than 10
It would help if you'd please use parentheses to indicate clearly what is to be multiplied or divided by what.
I am assuming (not claiming that I know) you meant:
(12f-16) (5)
------------ divided by --------------
16 9f^2 - 16
Factor as much as possible before attempting division:
4(3f-4) 5
--------- divided by -----------------
16 (3f-4)(3f+4)
This is equivalent to multiplying as follows:
4(3f-4) (3f-4)(3f+4)
---------- * -----------------
16 5
Is this what you meant? If so, please finish the work. If not, please copy down the original problem making liberal use of parentheses for clarity.
x = 5i x =-5i
Step-by-step explanation:
x^2+25=0
Rewriting
x^2 - (-25)=0
Writing as the difference of squares
a^2 - b^2= (a-b) (a+b)
where a = x and b = (sqrt(-25)) =±5i
( x-5i) ( x+5i) =0
Using the zero product property
x-5i =0 x+5i =0
x = 5i x =-5i