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3 years ago

Determine the infinite limit. lim x→−9− x + 8 x + 9

Mathematics

1 answer:

Serga [27]3 years ago

8 0

If given
$\lim_{x \to \ -9} (-x+8x+9)$
then
$\lim_{x \to \ -9} (-x+8x+9)=-54.$

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erma4kov [3.2K]

I believe the answer is 8

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3 years ago

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Zip codes for the Houston area are five digit numbers with 7 as the first 2 digits of each zip code. The third digit can be 0, 3

djyliett [7]

Answer:

There are 400 possible zip codes in the Houston area

Step-by-step explanation:

Here, we want to calculate the possible number of zip codes in the Houston area

We have 5 digits to form

77 is the first two digits ( this is fixed)

For the third digit, we are selecting 1 number out of 0,3,4 or 5

This means 4 C 1

The remaining digits can be any digits

We have 0-9, a total of 10 digits

The first will be 10 C 1 and the second last digit too is 10 C 1

So the number of possible zip codes will be;

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3 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

$u=x$ $dv=e^(2x)\cdot{dx}$

$du=dx$ $v=2\cdot{e^(2x)}$

$\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du$

$\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx$

$\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C$

We can therefore determine that if x tends to 0 the limit is -1

$\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1$

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3 years ago

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Question 11.b

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The area of an 20 -cm-wide rectangle is 440 cm. What is its length?

Nataly [62]

Answer:

22cm

Step-by-step explanation:

440÷20

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3 years ago