Answer:
The answer to the given question can be given as:
The value of *iptr is 7. and the value of iptr is dynamic.
Explanation:
In the c++ code, it is defined that x is an integer variable that assigns a value which is 7. Then we define a pointer variable that is *iptr. This variable holds an address of the x variable. When we print the value of the iptr variable. if we use the expression *iptr to print value of the pointer variable by cout that is used in c++ for pint values. so the value of the iptr is 7. If we use the expression iptr sent to cout so we show the address of the variable x. In the pointer, it manages the addresses of dynamically allocated so the address of the variable is changed on execution time.
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Answer:</h2><h2>
Oh yes you can. </h2>
Click slowly twice the folder.
Right click and choose rename.
def min(x,y):
smallest = x
if y < smallest:
smallest = y
return smallest
x = min(2,1)
print("The min is "+str(x))
Although I wouldn't recommend using the name min for a function because min is the name of an existing function. Best of luck.
I had 7 assignments all do at the same time for different classes. They were all incredibly tedious so I strategized and did the assignments that I knew well first, then completed the others. I evaluated the pros and cons of this strategy and decided that if I had done the harder ones first it would have taken more time and I would have been too stressed to complete the others. I hope that helps!
Answer:
twos complement value is (-2^15 -1) -32768 to 32767.
excess notation value is -32768 to 32767.
unsigned binary value is (2^16) 0 to 65535
Explanation:
Excess notation: used to represent signed integers. Always uses fixed number of bits with leftmost representing the sign.
Twos complement notation: As opposed to excess notation, a sign bit of 0 is used to represent the non-negative (+) sign and a 1 for the negative (-); again, zero is included in the non-negative set.
Unsigned Binary values: are binary values/bits that don't have signs
