5.7... not for sure. i think im wrong but idk
All you do is distribute you multiply x x 4 then 5 times 4 and then you divide 20 by 4 then x equals 5
A=5i+2j
B=2i-3j
C=-8i+3j
we find the vectors of AB, BC & AC:
AB=(2-5)i+(-3-2)j=-3i-5j
BC=(-8-2)i+(3-(-3))j=-10i+6j
AC=(-8-5)i+(3-2)j=-13i+j
now if the dot product of two of these vectors result in zero, it means that those vectors (representing the triangle sides) are perpendicular to each other (which means triangle ABC is a right-angled triangle)
let's try:
AB.BC=(-3)(-10)+(-5)(6)=30-30=0
thus the triangle ABC is a right-angled triangle.
Answer:
point form (-36,4) equation form x=−36,y=4
Step-by-step explanation: