Which ordered pair is a solution to the system of equations?
1 answer:
Answer:
(-2, -3)
Step-by-step explanation:
We assume your system of equations is ...
- 2x - y = -1
- 2x -4y = 8
You can subtract the second equation from the first to get
... (2x -y) -(2x -4y) = (-1) -(8)
... 3y = -9 . . . . . collect terms
... y = -3 . . . . . . divide by 3 . . . . this is sufficient to identify the correct answer
Substituting into the first equation, we have ...
... 2x -(-3) = -1
... 2x = -4 . . . . . add -3
... x = -2 . . . . . . .divide by 2
Now, we're sure the answer is (x, y) = (-2, -3).
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SOLUTION
Write out the equation given
The zeros of the polynomial is obtain by equating the polynomial to zero.
Hence
Equate each product to zero, we have
The zeros of the polynomial are
The zeros of the polynomials is 0 and 3
the multiplicity of multiple zeros is the number of times the zeros of the polynomial occur which is obtain from the degree of each terms in the polynomial.
Hence
Then
x =0 has the multiplicity of 2
For
x = 3 has a multiplicity of 3